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1 / + 1 / + 1 / 1 / = (A) 1 / (B) 1 /

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CEO
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1 / + 1 / + 1 / 1 / = (A) 1 / (B) 1 /  [#permalink] New post 16 Jun 2007, 21:30
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17. 1 / [(2)^10] + 1 / [(2)^11] + 1 / [(2)^12] 1 / [(2)^12] =

(A) 1 / [(2)^7]
(B) 1 / [(2)^8]
(C) 1 / [(2)^9]
(D) 1 / [(2)^13]
(E) 1 / [(2)^45]
Director
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Re: PS1000 26 #17 [#permalink] New post 16 Jun 2007, 21:37
bmwhype2 wrote:
17. 1 / [(2)^10] + 1 / [(2)^11] + 1 / [(2)^12] 1 / [(2)^12] =

(A) 1 / [(2)^7]
(B) 1 / [(2)^8]
(C) 1 / [(2)^9]
(D) 1 / [(2)^13]
(E) 1 / [(2)^45]



is your question complete. the last part seems incorrect.
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 [#permalink] New post 17 Jun 2007, 07:48
Hi, please confirm whether your question is correct or not.

I think last part is incorrect.
  [#permalink] 17 Jun 2007, 07:48
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