Find all School-related info fast with the new School-Specific MBA Forum
Learn more about the recent changes... close

It is currently 25 May 2013, 16:25
Customize  |  Hide

Search
Register
New posts
Unanswered

1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) divided by

  Question banks Downloads My Bookmarks Reviews  
  Oldest Best Reply
Search for:
 
Print view
First unread post
Author Message
TAGS:
Intern
Intern
Joined: 02 Mar 2007
Posts: 27
Followers: 0

Kudos [?]: 1 [0], given: 0

GMAT Tests User
1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) divided by [#permalink] New post 09 Aug 2007, 13:06
(1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) divided by
(1/3)+(1/4)+(1/5)+(1/6)+(1/7)

anyone know a fast and easy way to solve this?
Director
Director
User avatar
Joined: 12 Jul 2007
Posts: 875
Followers: 8

Kudos [?]: 135 [0], given: 0

GMAT Tests User
 [#permalink] New post 09 Aug 2007, 13:51
EDIT: nevermind, just noticed the terms in the denominator are added to one another, not multiplied
Director
Director
User avatar
Joined: 03 May 2007
Posts: 903
Schools: University of Chicago, Wharton School
Followers: 4

Kudos [?]: 30 [0], given: 6

GMAT Tests User
Re: arithmatic challenge [#permalink] New post 09 Aug 2007, 14:24
madcowudub wrote:
(1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) divided by
(1/3)+(1/4)+(1/5)+(1/6)+(1/7)

anyone know a fast and easy way to solve this?


= (1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) / (1/3)+(1/4)+(1/5)+(1/6)+(1/7)
= (4x5x6x7x8) / [(4x5x6x7) + (3x5x6x7) + (3x4x6x7) + (3x4x5x7) + (3x4x5x6)]
= (4x5x6x7x8) / [6(4x5x7) + (3x5x7) + (3x4x7) + (2x5x7) + (3x4x5)]
= (4x5x7x8) / [(4x5x7) + (3x5x7) + (3x4x7) + (2x5x7) + (3x4x5)]
= 1120 / (140 + 105 + 84 + 70 + 60)
= 1120 / 459
VP
VP
Joined: 10 Jun 2007
Posts: 1478
Followers: 5

Kudos [?]: 70 [0], given: 0

GMAT Tests User
Re: arithmatic challenge [#permalink] New post 09 Aug 2007, 17:26
madcowudub wrote:
(1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) divided by
(1/3)+(1/4)+(1/5)+(1/6)+(1/7)

anyone know a fast and easy way to solve this?


Top part = (4/3)*(5/4)*(6/5)*(7/6)*(8/7) = 8/3
Below = [(1/3) + (1/6)] + (1/4) + (1/5) + (1/7) = [[(1/2)] + (1/4)] + [(1/5) + (1/7)] = [3/4] + [12/35]
At this point, if the answer is some sort of decimal, I would estimate 12/35 to 12/36 ~= 1/3
Then move on.
Otherwise, I would just solve the three fractions I got.
Director
Director
User avatar
Joined: 03 May 2007
Posts: 903
Schools: University of Chicago, Wharton School
Followers: 4

Kudos [?]: 30 [0], given: 6

GMAT Tests User
Re: arithmatic challenge [#permalink] New post 09 Aug 2007, 17:38
bkk145 wrote:
madcowudub wrote:
(1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) divided by
(1/3)+(1/4)+(1/5)+(1/6)+(1/7)

anyone know a fast and easy way to solve this?


Top part = (4/3)*(5/4)*(6/5)*(7/6)*(8/7) = 8/3

Below = [(1/3) + (1/6)] + (1/4) + (1/5) + (1/7) = [[(1/2)] + (1/4)] + [(1/5) + (1/7)] = [3/4] + [12/35]

At this point, if the answer is some sort of decimal, I would estimate 12/35 to 12/36 ~= 1/3

Then move on.
Otherwise, I would just solve the three fractions I got.


i like your approach. excellent. we are almost there.
Re: arithmatic challenge   [#permalink] 09 Aug 2007, 17:38
    Similar topics Author Replies Last post
Similar
Topics:
 New posts Dividing a team Bhai 4 30 Aug 2004, 13:46
New posts dividing bmwhype2 5 12 Nov 2007, 13:26
New posts 2 Dividing eaakbari 8 26 Mar 2010, 05:13
New posts EXPERTS_POSTS_IN_THIS_TOPIC Dividing Equations Bigred2008 5 08 Dec 2010, 19:00
Display posts from previous: Sort by

1+1/3)(1+1/4)(1+1/5)(1+1/6)(1+1/7) divided by

  Question banks Downloads My Bookmarks Reviews  
Print view
First unread post

Moderators: Bunuel, VeritasPrepKarishma

Search for:


cron

GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.

Main navigation

GMAT Resources

Partners

MBA Resources

www.gmac.com|www.mba.com