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(1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) [#permalink] New post 29 Dec 2012, 04:58


  15% (low)

Question Stats:

84% (01:58) correct 15% (01:09) wrong based on 143 sessions

(A) (1/2)^(-48)
(B) (1/2)^(-11)
(C) (1/2)^(-6)
(D) (1/8)^(-11)
(E) (1/8)^(-6)
[Reveal] Spoiler: OA
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Re: (1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) [#permalink] New post 29 Dec 2012, 05:01
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Re: (1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) [#permalink] New post 29 Dec 2012, 05:14
Expert's post
Walkabout wrote:

(A) (1/2)^(-48)
(B) (1/2)^(-11)
(C) (1/2)^(-6)
(D) (1/8)^(-11)
(E) (1/8)^(-6)

whenevr you see a fraction raised to a negative power think reciprocal

so we have : 2^3 * 4^2 * 16^1

Consolidate: 2^3 * 2^4 * 2^4

Clearly as you can see we have 2^11 only B fits

otherwise take the reciprocal of 2^11 ----> 1/2^-11

B is the best

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Re: (1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) [#permalink] New post 10 Mar 2014, 02:47
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Re: (1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1) [#permalink] New post 20 Mar 2014, 23:21
Answer = B

Keep the base as 2 & modify the powers accordingly


= (\frac{1}{2})^{-3}(\frac{1}{2})^{-4}(\frac{1}{2})^{-4}

With the base the same, add the powers

-3-4-4 = -11


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Re: (1/2)^(-3)*(1/4)^(-2)*(1/16)^(-1)   [#permalink] 20 Mar 2014, 23:21
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