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# 1/(2 - sqrt(3)) = ? (m25#36)

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1/(2 - sqrt(3)) = ? (m25#36) [#permalink]

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15 Feb 2012, 07:04
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$$\frac{1}{2 - \sqrt{3}} = ?$$

(A) $$\sqrt{3} - 2$$
(B) $$2 + \sqrt{3}$$
(C) $$\sqrt{2} + \sqrt{3}$$
(D) $$2 - \sqrt{3}$$
(E) $$\sqrt{3} + 4$$
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Joined: 06 Oct 2011
Posts: 165
Schools: Wharton '15, CBS '15
GMAT Date: 06-30-2012
GPA: 3.7
WE: Accounting (Insurance)
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Re: 1/(2 - sqrt(3)) = ? (m25#36) [#permalink]

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15 Feb 2012, 08:16
1/(2- Sqrt3)

in order to eliminate the sq root from the bottom you must multiply by (2+sqrt3) which;
1(2+sqrt3) = 2+sqrt3 = 2+sqrt3
__________
(2-sqrt3)(2+sqrt3) = 4-2sqrt3+2sqrt3 -3 = 1
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Re: 1/(2 - sqrt(3)) = ? (m25#36) [#permalink]

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22 Feb 2012, 11:54
I solved it in a similar fashion. This was not bad at all...
Re: 1/(2 - sqrt(3)) = ? (m25#36)   [#permalink] 22 Feb 2012, 11:54
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# 1/(2 - sqrt(3)) = ? (m25#36)

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