Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 06 May 2016, 17:27

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# 1) For every positive even integer n, function h(n) is

Author Message
Manager
Joined: 17 Jul 2006
Posts: 50
Followers: 0

Kudos [?]: 4 [1] , given: 0

1) For every positive even integer n, function h(n) is [#permalink]

### Show Tags

24 Nov 2006, 14:25
1
KUDOS
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

1) For every positive even integer n, function h(n) is defined to be the product of all of the even integer from 2 to n, inclusive. If p is the smallest prime factor of h(100) + 1, then p is:

a) Between 2 and 10
b) Between 10 and 20
c) Between 20 and 30
d) Between 30 and 40
e) Greater than 40

2) For which of the following function f is f(x) = f(1 â€“ x) for all x?

a) f(x) = 1 â€“ x
b) f(x) = 1 â€“ x^2
c) f(x) = (x^2) â€“ (1 â€“ x^2)
d) f(x) = (x^2)(1 â€“ x^2)
e) f(x) = (x) / (1- x)

3) Last year a certain bond with a face value of $5000, yielded 8% of its face value in interest. If that interest was approximately 6.5% of the bondâ€™s selling price, approximately what was the bondâ€™s selling price? Answer is$6154

4) A certain company employs 6 senior officers and 4 junior officers. If company wants to make up 3 senior officers and 1 junior officers as a group. How many different groups are possible?
Manager
Joined: 25 May 2006
Posts: 227
Followers: 1

Kudos [?]: 38 [1] , given: 0

### Show Tags

24 Nov 2006, 15:17
1
KUDOS
2)
I believe there is something wrong with answer choice D. I think answer D should be f(x) = (x^2)(1 â€“ x)^2.
If x=2 then f(x)=f(1-x) --> f(2)=f(-1) and option D yields 4 with x=2 and x=-1

3)
5000(8%)=400
400=6.58%(x) --> x=6,154 = (4000/65)(100) =(800/13)(100) --> 6.154

4)
6C3=20
20*4=80
_________________

Who is John Galt?

Manager
Joined: 17 Jul 2006
Posts: 50
Followers: 0

Kudos [?]: 4 [1] , given: 0

### Show Tags

24 Nov 2006, 17:03
1
KUDOS
I still do not understand #4. could you please explain number 4?
Director
Joined: 28 Dec 2005
Posts: 921
Followers: 2

Kudos [?]: 42 [1] , given: 0

### Show Tags

24 Nov 2006, 17:23
1
KUDOS
4.

6C3 * 4C1 = 80

The way to select 3 senior officers from 6 is 6C3.
The way to select 1 junior officer from 4 is 4C1.

Order does not matter, hence combination.
Manager
Joined: 17 Jul 2006
Posts: 50
Followers: 0

Kudos [?]: 4 [1] , given: 0

### Show Tags

24 Nov 2006, 18:40
1
KUDOS
how did you get 80 in Problem 4?
Manager
Joined: 25 May 2006
Posts: 227
Followers: 1

Kudos [?]: 38 [1] , given: 0

### Show Tags

24 Nov 2006, 19:04
1
KUDOS
g1m2a3t406 wrote:
how did you get 80 in Problem 4?

Letâ€™s say that the Seniors are: ABCDEF and the Juniors are: xywz

First focus on the Seniors. You can make 20 possible 3 groups of the total 6 --> (6!)/[(3!)(3!)] = 20
ABC
ABD
ABE
ABF
BCD
BCE
.
.
.
.
20 combinations

Now focus on the 3 seniors group + 1 junior.
The ABC group can have the x OR y OR w OR z --> so for ABC you have 4 possible juniors and for ABD also 4 possible juniors and so onâ€¦â€¦.

So,
From the 20 seniors groups you have 4 possible juniors:
=(4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4) = (20)(4) = 80
_________________

Who is John Galt?

VP
Joined: 25 Jun 2006
Posts: 1172
Followers: 2

Kudos [?]: 96 [1] , given: 0

### Show Tags

24 Nov 2006, 22:59
1
KUDOS
2nd question has no answer. u posted it wrongly i guess.

agree with the rest.
Display posts from previous: Sort by