kheriapiyush@indiatimes.c wrote:

I would like to have the explanation for the 1st one.

I tried the following:-

1) Total no. of possibilities = 6*6*6 = 216

No. of events where all the three are equal = 6

No. of events when none are eqaul = 6*5*4 = 120

Therefore the no. of events when two are equal and third different

= 216-6-120 = 90

Therefore Probability that 2 are equal and third is different = 90 / 216

= 5/12

The remaining two I got the answers same as 5/18 and 5/324 respectively.

I agree with indiatimes on this one. My method was the same:

All three numbers the same we have 6/216.

All three different we have 120/216.

So the remainder is 90/216, reducing to 5/12.

Comments?