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10 t-shirts are available to choose. 5 of them are printed, [#permalink]
20 Jun 2004, 08:00
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10 t-shirts are available to choose. 5 of them are printed, and 5 of them are plain t-shirts. If 3 t-shirts are to be selected at random from the 10, what is the probability that at least one of them is a printed t-shirt.
Please explain the steps (procedure) _________________
10 t-shirts are available to choose. 5 of them are printed, and 5 of them are plain t-shirts. If 3 t-shirts are to be selected at random from the 10, what is the probability that at least one of them is a printed t-shirt.
Please explain the steps (procedure)
1. Probability of at least 1 being a printed = 1 - P(none of them is printed).
Re: 10 t-shirts are available to choose. 5 of them are printed, [#permalink]
14 Jul 2014, 20:58
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carsen wrote:
10 t-shirts are available to choose. 5 of them are printed, and 5 of them are plain t-shirts. If 3 t-shirts are to be selected at random from the 10, what is the probability that at least one of them is a printed t-shirt.
Please explain the steps (procedure)
You have 10 t-shirts. You need to choose 3 of them. You can do this in 10C3 = 10*9*8/3*2*1 = 120 ways.
You have 5 plain t-shirts. You can choose 3 out of them in 5C3 = 5*4/2 = 10 ways.
So you have total 120 ways of picking 3 t-shirts out of 10. In 10 of those ways, you pick all plain t-shirts. So what happens in the rest of the 110 ways? In those, you must be picking up at least one printed t-shirt.
So probability of picking at least one printed t-shirt = 110/120 = 11/12 _________________
Re: 10 t-shirts are available to choose. 5 of them are printed, [#permalink]
23 Sep 2015, 12:39
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Re: 10 t-shirts are available to choose. 5 of them are printed, [#permalink]
23 Sep 2015, 13:17
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carsen wrote:
10 t-shirts are available to choose. 5 of them are printed, and 5 of them are plain t-shirts. If 3 t-shirts are to be selected at random from the 10, what is the probability that at least one of them is a printed t-shirt.
When it comes to probability questions involving "at least," it's best to try using the complement, as the above solutions have done. However, what if you didn't spot that shortcut? No problem, it will just take us a little bit longer.
P(at least 1 printed shirt) = (# of outcomes with at least 1 printed shirt)/(TOTAL # of possible outcomes)
Always start with the denominator.
TOTAL # of possible outcomes We have 10 shirts and we must select 3. Since the order in which we select the shirts doesn't matter, we can use combinations. We can select 3 shirts from 10 shirt in 10C3 ways (= 120 outcomes)
# of outcomes with at least 1 printed shirt We have 3 cases: Case 1: 1 printed shirt and 2 plain. So, select 1 of the 5 printed, and select 2 of the 5 plain. # of outcomes = (5C1)(5C2) = (5)(10) = 50 Case 2: 2 printed shirts and 1 plain. So, select 2 of the 5 printed, and select 1 of the 5 plain. # of outcomes = (5C2)(5C1) = (10)(5) = 50 Case 3: 3 printed shirts and 0 plain. So, select 3 of the 5 printed, and select 0 of the 5 plain. # of outcomes = (5C3)(5C0) = (10)(1) = 10
Total number of outcomes = 50 + 50 + 10 = 110
So, P(at least 1 printed shirt) = 110/120 = 11/12
Cheers, Brent _________________
Brent Hanneson - Founder of GMAT Prep Now, a free & comprehensive GMAT course with: - over 500 videos (35 hours of instruction) - over 800 practice questions - 2 full-length practice tests and other bonus offers - http://www.gmatprepnow.com/
Re: 10 t-shirts are available to choose. 5 of them are printed, [#permalink]
25 Sep 2015, 07:58
VeritasPrepKarishma wrote:
carsen wrote:
10 t-shirts are available to choose. 5 of them are printed, and 5 of them are plain t-shirts. If 3 t-shirts are to be selected at random from the 10, what is the probability that at least one of them is a printed t-shirt.
Please explain the steps (procedure)
You have 10 t-shirts. You need to choose 3 of them. You can do this in 10C3 = 10*9*8/3*2*1 = 120 ways.
You have 5 plain t-shirts. You can choose 3 out of them in 5C3 = 5*4/2 = 10 ways.
So you have total 120 ways of picking 3 t-shirts out of 10. In 10 of those ways, you pick all plain t-shirts. So what happens in the rest of the 110 ways? In those, you must be picking up at least one printed t-shirt.
So probability of picking at least one printed t-shirt = 110/120 = 11/12
Karishma,
This is the combinatorics approach if I am not wrong. Can you tell me how to solve this with probability approach. _________________
Freedom is not a gift...It is a responsibility to pass on.....
Re: 10 t-shirts are available to choose. 5 of them are printed, [#permalink]
25 Sep 2015, 08:39
Learning4mU wrote:
Karishma,
This is the combinatorics approach if I am not wrong. Can you tell me how to solve this with probability approach.
Emmanuel posted a nice probability approach above.
Cheers, Brent _________________
Brent Hanneson - Founder of GMAT Prep Now, a free & comprehensive GMAT course with: - over 500 videos (35 hours of instruction) - over 800 practice questions - 2 full-length practice tests and other bonus offers - http://www.gmatprepnow.com/
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