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100 people are attending a newspaper conference. 45 of them [#permalink]

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16 Feb 2012, 21:34

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100 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors?

100 people are attending a newspaper conference. 45 of them [#permalink]

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16 Feb 2012, 21:51

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calreg11 wrote:

100 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? 6 16 17 33 84

Re: 100 people are attending a newspaper conference. 45 of them [#permalink]

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05 Mar 2012, 13:25

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question stem total=100 W=45 E= more than 38 W-and-E=x Neither=2x x? answer- 100=45+39+2x-x (to maximize x we need to minimize E. that is why E=39 the least value) x=16 _________________

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Re: 100 people are attending a newspaper conference. 45 of them [#permalink]

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11 Apr 2014, 02:32

calreg11 wrote:

100 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors?

A. 6 B. 16 C. 17 D. 33 E. 84

W + E - Both + Neither = 100

45 + E - (x) + 2x = 100

45 + E + x = 100

Now let us plug in answer options:

We cannot plug in 84 as E will become negative If we plug in x = 33 then E = 22 (Wrong as there are more than 38 editors) If we plug in x = 17 then E = 38 (Wrong as there are more than 38 editors) Hence answer is x= 16

Re: 100 people are attending a newspaper conference. 45 of them [#permalink]

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03 Aug 2014, 17:32

Bunuel wrote:

calreg11 wrote:

100 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? 6 16 17 33 84

100=45+{Editors}-x+2x --> x=55-{Editors}. We want to maximize x, thus we should minimize {Editors}, minimum possible value of {Editors} is 39, thus x={Both}=55-39=16.

Answer: B.

Hope it's clear.

Hi Bunuel,

Can you please explain "100=45+{Editors}-x+2x --> x=55-{Editors}. We want to maximize x, thus we should minimize {Editors}, minimum possible value of {Editors} is 39, thus x={Both}=55-39=16."

I understand the concept that when we want to maximize something, we want to minimize the other, but why do we want to minimize editors? Aren't we trying to find the greatest number of editors AND writers? Shouldn't we want to MAXIMIZE Editors AND Writers?

Re: 100 people are attending a newspaper conference. 45 of them [#permalink]

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03 Aug 2014, 20:14

This would be my approach,

there are 45 writers.. let that be; now lets say there are 38 editors, 'x' of whom are also writers, who are already accounted for as writers in that 45. So the number of editors who are not writers is (38-x).

Now the number of people who are neither writers or editors is 100 - [( No.of writers) + (No.of Editors who are not writers)], and we know this is 2x

100 - [ 45 + ( 38 -x ) ] = 2x x= 17 but since number of editors is MORE than 38, 'x' has to be less than 17, so if we assume no.of editors is just 1 more at 39, then x=16.

Re: 100 people are attending a newspaper conference. 45 of them [#permalink]

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12 Aug 2014, 09:50

Expert's post

russ9 wrote:

Bunuel wrote:

calreg11 wrote:

100 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? 6 16 17 33 84

100=45+{Editors}-x+2x --> x=55-{Editors}. We want to maximize x, thus we should minimize {Editors}, minimum possible value of {Editors} is 39, thus x={Both}=55-39=16.

Answer: B.

Hope it's clear.

Hi Bunuel,

Can you please explain "100=45+{Editors}-x+2x --> x=55-{Editors}. We want to maximize x, thus we should minimize {Editors}, minimum possible value of {Editors} is 39, thus x={Both}=55-39=16."

I understand the concept that when we want to maximize something, we want to minimize the other, but why do we want to minimize editors? Aren't we trying to find the greatest number of editors AND writers? Shouldn't we want to MAXIMIZE Editors AND Writers?

Thanks

We want to maximize x, which is {both writers and editors}. To maximize x, we need to minimize {Editors} because x = 55 - {Editors}.

Re: 100 people are attending a newspaper conference. 45 of them [#permalink]

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