Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
It appears that you are browsing the GMAT Club forum unregistered!
Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club
Registration gives you:
Tests
Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.
Applicant Stats
View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more
Books/Downloads
Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
12 Easy Pieces (or not?) [#permalink]
21 Jan 2012, 05:10
30
This post received KUDOS
Expert's post
70
This post was BOOKMARKED
After posting some 700+ questions, I've decided to post the problems which are not that hard. Though each question below has a trap or trick so be careful when solving. I'll post OA's with detailed solutions after some discussion. Good luck.
1. There are 5 pairs of white, 3 pairs of black and 2 pairs of grey socks in a drawer. If four socks are picked at random what is the probability of getting two socks of the same color? A. 1/5 B. 2/5 C. 3/4 D. 4/5 E. 1
2. If x is an integer and 9<x^2<99, then what is the value of maximum possible value of x minus minimum possible value of x? A. 5 B. 6 C. 7 D. 18 E. 20
3. Fanny and Alexander are 360 miles apart and are traveling in a straight line toward each other at a constant rate of 25 mph and 65 mph respectively, how far apart will they be exactly 1.5 hours before they meet? A. 25 miles B. 65 miles C. 70 miles D. 90 miles E. 135 miles
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x? A. -4<y-x<4 B. -2<y-x<4 C. -12<y-x<4 D. -12<y-x<12 E. 4<y-x<12
5. The angles in a triangle are x, 3x, and 5x degrees. If a, b and c are the lengths of the sides opposite to angles x, 3x, and 5x respectively, then which of the following must be true? I. c>a+b II. c^2>a^2+b^2 III. c/a/b=10/6/2
A. I only B. II only C. III only D. I and III only E. II and III only
6. Anna has 10 marbles: 5 red, 2 blue, 2 green and 1 yellow. She wants to arrange all of them in a row so that no two adjacent marbles are of the same color and the first and the last marbles are of different colors. How many different arrangements are possible? A. 30 B. 60 C. 120 D. 240 E. 480
7. After 2/9 of the numbers in a data set A were observed, it turned out that 3/4 of those numbers were non-negative. What fraction of the remaining numbers in set A must be negative so that the total ratio of negative numbers to non-negative numbers be 2 to 1? A. 11/14 B. 13/18 C. 4/7 D. 3/7 E. 3/14
8. There are 15 black chips and 5 white chips in a jar. What is the least number of chips we should pick to guarantee that we have 2 chips of the same color? A. 3 B. 5 C. 6 D. 16 E. 19
9. Julie is putting M marbles in a row in a repeating pattern: blue, white, red, green, black, yellow, pink. If the row begins with blue marble and ends with red marble, then which of the following could be the value of M? A. 22 B. 30 C. 38 D. 46 E. 54
11. The numbers {1, 3, 6, 7, 7, 7} are used to form three 2-digit numbers. If the sum of these three numbers is a prime number p, what is the largest possible value of p? A. 97 B. 151 C. 209 D. 211 E. 219
12. If \({-\frac{1}{3}}\leq{x}\leq{-\frac{1}{5}}\) and \({-\frac{1}{2}}\leq{y}\leq{-\frac{1}{4}}\), what is the least value of \(x^2*y\) possible? A. -1/100 B. -1/50 C. -1/36 D. -1/18 E. -1/6
Q11. Best strategy is to check answer choices. As we need to find the largest possible, good idea to start from the largest number. Lets start with E. 219 only way to reach 219 is to have 71, 73 and 76 which total 220 (Not a prime number)
D. 211 (77 + 71 + 63) = 211 and 211 is prime hence ans D
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x? A. -4<y-x<4 B. -2<y-x<4 C. -12<y-x<4 D. -12<y-x<12 E. 4<y-x<12
To get max value of y-x take max value of y and min value of x: 9-(-3)=12; To get min value of y-x take min value of y and max value of x: -7-(5)=-12;
Hence, the range of all possible values of y-x is -12<y-x<12.
Answer: D.
Those values of x and y you had considered would be right if there was an <= symbol at all the places where there are inequality signs. But, provided there is no = symbol along with < and >, then won't the range be -10 to +10? Please explain!
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x? A. -4<y-x<4 B. -2<y-x<4 C. -12<y-x<4 D. -12<y-x<12 E. 4<y-x<12
To get max value of y-x take max value of y and min value of x: 9-(-3)=12; To get min value of y-x take min value of y and max value of x: -7-(5)=-12;
Hence, the range of all possible values of y-x is -12<y-x<12.
Answer: D.
Those values of x and y you had considered would be right if there was an <= symbol at all the places where there are inequality signs. But, provided there is no = symbol along with < and >, then won't the range be -10 to +10? Please explain!
If y=8.9 and x=-2.9, then y-x=11.8. If y=-6.9 and x=4.9, then y-x=-11.8.
So, your range (-10 , 10) is clearly wrong.
Consider the following approach, we have -3<x<5 and -7<y<9,
Add y<9 and -3<x --> y-3<9+x --> y-x<12; Add -7<y and x<5 --> -7+x<y+5 --> -12<y-x;
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x? A. -4<y-x<4 B. -2<y-x<4 C. -12<y-x<4 D. -12<y-x<12 E. 4<y-x<12
To get max value of y-x take max value of y and min value of x: 9-(-3)=12; To get min value of y-x take min value of y and max value of x: -7-(5)=-12;
Hence, the range of all possible values of y-x is -12<y-x<12.
Answer: D.
Since, the question mentions -3<x<5 and -7<y<9 and not -3<=x<=5 and -7<=y<=9, i thought that x values are not inclusive -3 and 5; similarly y values are not inclusie -7 and 9. Is my thought correct?
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x? A. -4<y-x<4 B. -2<y-x<4 C. -12<y-x<4 D. -12<y-x<12 E. 4<y-x<12
To get max value of y-x take max value of y and min value of x: 9-(-3)=12; To get min value of y-x take min value of y and max value of x: -7-(5)=-12;
Hence, the range of all possible values of y-x is -12<y-x<12.
Answer: D.
Since, the question mentions -3<x<5 and -7<y<9 and not -3<=x<=5 and -7<=y<=9, i thought that x values are not inclusive -3 and 5; similarly y values are not inclusie -7 and 9. Is my thought correct?
Yes, your understanding is correct. _________________
7. After 2/9 of the numbers in a data set A were observed, it turned out that 3/4 of those numbers were non-negative. What fraction of the remaining numbers in set A must be negative so that the total ratio of negative numbers to non-negative numbers be 2 to 1? A. 11/14 B. 13/18 C. 4/7 D. 3/7 E. 3/14
If choose variable for set A there will be too many fractions to manipulate with, so pick some smart #: let set A contain 18 numbers.
"2/9 of the numbers in a data set A were observed" --> 4 observed and 18-4=14 numbers left to observe; "3/4 of those numbers were non-negative" --> 3 non-negative and 1 negative; Ratio of negative numbers to non-negative numbers to be 2 to 1 there should be total of 18*2/3=12 negative numbers, so in not yet observed part there should be 12-1=11 negative numbers. Thus 11/14 of the remaining numbers in set A must be negative.
Answer: A.
hey, here's my approach and i found this to be more simplified,
otal we have 2/9 our first fraction as 2, 9 are co primes take its multiple 18 as our total kit.
2/9 = 4 of which 3 are NN and 1 is Negative, rest we have 14 of 18. given ration of Non negative to negative is 1: 2 , 3 parts are 18 and this implies 2 parts are 12 but we already have one negative in first 4 so, we need another 11/18 done
For #7. How can we assume there is no 0 in set A? It just says numbers (either negative or non negative) 0 is neither. So I used 0 too and got the wrong answer.
For #7. How can we assume there is no 0 in set A? It just says numbers (either negative or non negative) 0 is neither. So I used 0 too and got the wrong answer.
Thanks
Please read the solution again: 12-easy-pieces-or-not-126366.html#p1033933 Pay attention to the term "non-negative" there (0 and positive) and you'll notice that no assumtion was made. _________________
9. Julie is putting M marbles in a row in a repeating pattern: blue, white, red, green, black, yellow, pink. If the row begins with blue marble and ends with red marble, then which of the following could be the value of M? A. 22 B. 30 C. 38 D. 46 E. 54
There are total of 7 different color marbles in a pattern. Now, as the row begins with blue marble and ends with red marble (so ends with 3rd marble in a pattern) then M=7k+3. The only answer choice which is multiple of 7 plus 3 is 38=35+3.
Answer: C.
Sorry, this may be a silly thing to ask, I don't understand the problem. What exactly is it asking?
Can someone please explain?
I get that it is asking how many marbles does Julie have. Here is what I am understanding:
Basically there are marbles with seven different colors. Out of which blue, white and red always stay in that order since these three form a pattern. The rest of the four marbles of different colors can be in any order. But the 8th marble will always be blue followed by white and followed by white. Is this thinking/approach correct??
If yes, where does 38 come from and if it is not correct, please tell me what's wrong.
9. Julie is putting M marbles in a row in a repeating pattern: blue, white, red, green, black, yellow, pink. If the row begins with blue marble and ends with red marble, then which of the following could be the value of M? A. 22 B. 30 C. 38 D. 46 E. 54
There are total of 7 different color marbles in a pattern. Now, as the row begins with blue marble and ends with red marble (so ends with 3rd marble in a pattern) then M=7k+3. The only answer choice which is multiple of 7 plus 3 is 38=35+3.
Answer: C.
Sorry, this may be a silly thing to ask, I don't understand the problem. What exactly is it asking?
Can someone please explain?
I get that it is asking how many marbles does Julie have. Here is what I am understanding:
Basically there are marbles with seven different colors. Out of which blue, white and red always stay in that order since these three form a pattern. The rest of the four marbles of different colors can be in any order. But the 8th marble will always be blue followed by white and followed by white. Is this thinking/approach correct??
If yes, where does 38 come from and if it is not correct, please tell me what's wrong.
Thanks
No, that's not correct.
The question asks to determine how many marbles Julie has.
The pattern is always the same {blue, white, red, green, black, yellow, pink}{blue, white, red, green, black, yellow, pink}{blue, white, red, green, black, yellow, pink}...
At some point Julie does not have enough marbles to end the pattern and the row ends with a red marble: {blue, white, red}.
For example, it could happen if she had 7+3=10 marbles: {blue, white, red, green, black, yellow, pink}{blue, white, red}
9. Julie is putting M marbles in a row in a repeating pattern: blue, white, red, green, black, yellow, pink. If the row begins with blue marble and ends with red marble, then which of the following could be the value of M? A. 22 B. 30 C. 38 D. 46 E. 54
There are total of 7 different color marbles in a pattern. Now, as the row begins with blue marble and ends with red marble (so ends with 3rd marble in a pattern) then M=7k+3. The only answer choice which is multiple of 7 plus 3 is 38=35+3.
Answer: C.
Sorry, this may be a silly thing to ask, I don't understand the problem. What exactly is it asking?
Can someone please explain?
I get that it is asking how many marbles does Julie have. Here is what I am understanding:
Basically there are marbles with seven different colors. Out of which blue, white and red always stay in that order since these three form a pattern. The rest of the four marbles of different colors can be in any order. But the 8th marble will always be blue followed by white and followed by white. Is this thinking/approach correct??
If yes, where does 38 come from and if it is not correct, please tell me what's wrong.
Thanks
No, that's not correct.
The question asks to determine how many marbles Julie has.
The pattern is always the same {blue, white, red, green, black, yellow, pink}{blue, white, red, green, black, yellow, pink}{blue, white, red, green, black, yellow, pink}...
At some point Julie does not have enough marbles to end the pattern and the row ends with a red marble: {blue, white, red}.
For example, it could happen if she had 7+3=10 marbles: {blue, white, red, green, black, yellow, pink}{blue, white, red}
I think answer should change if we skip to mention "at least" in the question :
If four socks are picked at random what is the probability of getting two socks of the same color?
If four socks are picked at random what is the probability of getting (at least) two socks of the same color? _________________
Piyush K ----------------------- Our greatest weakness lies in giving up. The most certain way to succeed is to try just one more time. ― Thomas A. Edison Don't forget to press--> Kudos My Articles: 1. WOULD: when to use?| 2. All GMATPrep RCs (New) Tip: Before exam a week earlier don't forget to exhaust all gmatprep problems specially for "sentence correction".
2. If x is an integer and 9<x^2<99, then what is the value of maximum possible value of x minus minimum possible value of x? A. 5 B. 6 C. 7 D. 18 E. 20
Also tricky. Notice that \(x\) can take positive, as well as negative values to satisfy \(9<x^2<99\), hence \(x\) can be: -9, -8, -7, -6, -4, 4, 5, 6, 7, 8, or 9. We asked to find the value of \(x_{max}-x_{min}\), ans since \(x_{max}=9\) and \(x_{min}=-9\) then \(x_{max}-x_{min}=9-(-9)=18\). [/square_root] Answer: D.
Hi bunel can you explain how we get max,min possible values from -9 to 9
2. If x is an integer and 9<x^2<99, then what is the value of maximum possible value of x minus minimum possible value of x? A. 5 B. 6 C. 7 D. 18 E. 20
Also tricky. Notice that \(x\) can take positive, as well as negative values to satisfy \(9<x^2<99\), hence \(x\) can be: -9, -8, -7, -6, -4, 4, 5, 6, 7, 8, or 9. We asked to find the value of \(x_{max}-x_{min}\), ans since \(x_{max}=9\) and \(x_{min}=-9\) then \(x_{max}-x_{min}=9-(-9)=18\). [/square_root] Answer: D.
Hi bunel can you explain how we get max,min possible values from -9 to 9
Sure.
Since x is an integer and 9<x^2<99, then the least value of x is -9 --> (-9)^2<99 (x cannot be -10 because 10^2=100>99). The same way, the max value of x is 9 --> 9^2<99 (x cannot be 10 because 10^2=100>99).
I have a question about the socks. How did you know that you are not required to answer for the option that only two socks are the same? From your answer I gather you took it as "at least" but it was not in the question stem. What are the rules of these assumptions?
4. If -3<x<5 and -7<y<9, which of the following represent the range of all possible values of y-x? A. -4<y-x<4 B. -2<y-x<4 C. -12<y-x<4 D. -12<y-x<12 E. 4<y-x<12
To get max value of y-x take max value of y and min value of x: 9-(-3)=12; To get min value of y-x take min value of y and max value of x: -7-(5)=-12;
Hence, the range of all possible values of y-x is -12<y-x<12.
Answer: D.
This answer is not 100% right, because there is not the sign <= but only <. therefore (assuming that X and Y are integers the answer is: (-6-(-4))<Y-X<(8-(-2))
As I’m halfway through my second year now, graduation is now rapidly approaching. I’ve neglected this blog in the last year, mainly because I felt I didn’...
Hilary Term has only started and we can feel the heat already. The two weeks have been packed with activities and submissions, giving a peek into what will follow...
Ninety-five percent of the Full-Time Class of 2015 received an offer by three months post-graduation, as reported today by Kellogg’s Career Management Center(CMC). Kellogg also saw an increase...