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50% (01:17) correct
49% (00:23) wrong based on 132 sessions

\frac{2^{(4-1)^2}}{2^{(3-2)}}=

A. 2^8 B. 2^7 C. 2^6 D. 2^5 E. 2^4

I'm overlooking something incredibly basic here. I know it. It's the first question I got on the GMAT prep math and I was shocked to see I got it WRONG. I've looked over it time and again, but can't find how to get the answer they are saying. They insist it's A, but I can take one look at that and see they are asking 2^6 over 2^2. Which would be 2^4. What am I missing?

Re: I'm missing something basic here, but no idea what [#permalink]
07 Nov 2010, 12:11

2

This post received KUDOS

Expert's post

Pollux wrote:

I'm overlooking something incredibly basic here. I know it. It's the first question I got on the GMAT prep math and I was shocked to see I got it WRONG. I've looked over it time and again, but can't find how to get the answer they are saying. They insist it's A, but I can take one look at that and see they are asking 2^6 over 2^2. Which would be 2^4. What am I missing?

Also please check the questions when posting. Original question is \frac{2^{(4-1)^2}}{2^{(3-2)}}=?

If exponentiation is indicated by stacked symbols, the rule is to work from the top down, thus: a^m^n=a^{(m^n)} and not (a^m)^n, which on the other hand equals to a^{mn}.

Re: I'm missing something basic here, but no idea what [#permalink]
07 Nov 2010, 12:25

Bunuel replied before I posted mine. It all makes sense now. Top down. Top down. Top down. Good to know!
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Re: I'm missing something basic here, but no idea what [#permalink]
08 Nov 2010, 15:53

Bunuel wrote:

Pollux wrote:

I'm overlooking something incredibly basic here. I know it. It's the first question I got on the GMAT prep math and I was shocked to see I got it WRONG. I've looked over it time and again, but can't find how to get the answer they are saying. They insist it's A, but I can take one look at that and see they are asking 2^6 over 2^2. Which would be 2^4. What am I missing?

Also please check the questions when posting. Original question is \frac{2^{(4-1)^2}}{2^{(3-2)}}=?

If exponentiation is indicated by stacked symbols, the rule is to work from the top down, thus: a^m^n=a^{(m^n)} and not (a^m)^n, which on the other hand equals to a^{mn}.

I am just curious as I got when the OP posted they said it was \frac{2^{(4-1)^2}}{2^{(3-1)}}=?

and when you answered it you changed the denominator's exponent from (3-1) to (3-2), was it just a typo by the OP? I"m confused because I got 2^7
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Remember that 2^{3^2} is not same to (2^3)^2 because the formulas are 2^{x^y} and (2^x)^y = 2^{xy}are different from each other and if we solve 2^{3^2} we get 2^9 (here solve from top to down) and by solving (2^3)^2we get 2^6=64 or 8^2=64

Please! check your Official Answer because the answer can't be 2^8 by solving with the forum timer, I got it wrong as it says that OA is A, which according to rule can't be (just explained above). _________________

"Don't be afraid of the space between your dreams and reality. If you can dream it, you can make it so." Target=780 http://challengemba.blogspot.com Kudos??

Remember that 2^{3^2} is not same to (2^3)^2 because the formulas are 2^{x^y} and (2^x)^y = 2^{xy}are different from each other and if we solve 2^{3^2} we get 2^9 (here solve from top to down) and by solving (2^3)^2we get 2^6=64 or 8^2=64

Please! check your Official Answer because the answer can't be 2^8 by solving with the forum timer, I got it wrong as it says that OA is A, which according to rule can't be (just explained above).

Hi, The question given by original poster was incorrect; it has been edited and corrected. Thanks.
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Re: 2^(4-1)^2/2^(3-2) [#permalink]
22 Oct 2013, 04:16

Expert's post

waltiebikkiebal wrote:

Small question, could there be an indicator of below 600 level questions? This is obviously a 400-500 level question, and it is a bit misleading for some of us to waste precious time on easy questions, when someone wants to practice questions of a higher level.

Thanks.

Check the tags please:

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