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# 2^2)-1))((2^2)+1))((2^4)+1))((2^8)+1))= A) (2^16)-1 B)

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Director
Joined: 05 Feb 2006
Posts: 902
Followers: 1

Kudos [?]: 51 [0], given: 0

2^2)-1))((2^2)+1))((2^4)+1))((2^8)+1))= A) (2^16)-1 B) [#permalink]  26 Nov 2006, 04:35
00:00

Difficulty:

(N/A)

Question Stats:

100% (02:08) correct 0% (00:00) wrong based on 2 sessions
((2^2)-1))((2^2)+1))((2^4)+1))((2^8)+1))=

A) (2^16)-1
B) (2^16)+1
C) (2^32)-1
D) (2^128)-1
E) 2^16((2^16)-1)
Director
Joined: 05 Feb 2006
Posts: 902
Followers: 1

Kudos [?]: 51 [0], given: 0

I did apply this formula but somehow managed to make a mistake... maybe rushed a bit too hard...
Yes now it works fine.

OA is A
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3 (2^2-1)(2^2+1)(2^4+1)(2^8+1)= 3 05 Jul 2012, 01:26
2^2-1)(2^2+1)(2^4+1)(2^8+1)= 2^16-1 2^16+1 2^32-1 1 10 Oct 2007, 19:52
5 (2^2-1)(2^2+1)(2^4+1)(2^8+1)= 5 28 Jul 2007, 13:38
b 1 23 Jan 2007, 04:45
b 6 04 Jul 2006, 10:40
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