2^2-1) (2^2+1) (2^4+4) (2^8+1)= (a)2^16-1 (b)2^16+1

Oldest

Best Reply

Author

Message

TAGS:

Manager

Joined: 11 Nov 2004

Posts: 80

Followers: 1

Kudos [?]: 0 [0], given: 0

2^2-1) (2^2+1) (2^4+4) (2^8+1)= (a)2^16-1 (b)2^16+1 [#permalink]

14 Jan 2005, 19:20

00:00

Question Stats:

0% (00:00) correct

0% (00:00) wrong

based on 0 sessions

(2^2-1) (2^2+1) (2^4+4) (2^8+1)=

(a)2^16-1
(b)2^16+1
(c)2^32-1
(d)2^128-1
(e)2^16(2^16-1)

Director

Joined: 07 Jun 2004

Posts: 638

Location: PA

Followers: 1

Kudos [?]: 60 [0], given: 22

[#permalink]

14 Jan 2005, 19:54

I am note sure whether i am reading the Q right My answer to this wud be E

Senior Manager

Joined: 22 Jun 2004

Posts: 399

Location: Bangalore, India

Followers: 1

Kudos [?]: 1 [0], given: 0

Re: PS [#permalink]

15 Jan 2005, 07:40

I think it is (2^4+1) than (2^4+4) . If that is so, I choose A.

Otherwise, none of the answers match.

Janice wrote:

(2^2-1) (2^2+1) (2^4+4) (2^8+1)=

(a)2^16-1
(b)2^16+1
(c)2^32-1
(d)2^128-1
(e)2^16(2^16-1)

_________________

Awaiting response,

Thnx & Rgds,
Chandra

Manager

Joined: 11 Nov 2004

Posts: 80

Followers: 1

Kudos [?]: 0 [0], given: 0

[#permalink]

15 Jan 2005, 09:47

sorry guys the question should be like this:

(2^2-1) (2^2+1) (2^4+1) (2^8+1)=

(a)2^16-1
(b)2^16+1
(c)2^32-1
(d)2^128-1
(e)2^16(2^16-1)

...and OA is A.Please explain how you solved it.

Intern

Joined: 15 Jan 2005

Posts: 2

Followers: 0

Kudos [?]: 0 [0], given: 0

[#permalink]

15 Jan 2005, 14:37

Hello Janice!
If u use the formula (a-b)(a+b)=a^2-b^2 u will easily solve this problem! So (2^2-1) (2^2+1) = (2^4-1)
(2^4-1) (2^4+1) = (2^8-1)
(2^8-1) (2^8+1) = (2^16-1)
the answer is A!
Good Luck!

Manager

Joined: 11 Nov 2004

Posts: 80

Followers: 1

Kudos [?]: 0 [0], given: 0

[#permalink]

15 Jan 2005, 15:05

AniAngel wrote:

Hello Janice!
If u use the formula (a-b)(a+b)=a^2-b^2 u will easily solve this problem! So (2^2-1) (2^2+1) = (2^4-1)
(2^4-1) (2^4+1) = (2^8-1)
(2^8-1) (2^8+1) = (2^16-1)
the answer is A!
Good Luck!

thanks

[#permalink] 15 Jan 2005, 15:05

		Similar topics	Author	Replies	Last post
Similar Topics:		2^2 -1) (2^2+1) (2^4+1) (2^8+1) = a) 2^16 - 1 b) 2^16 + 1 c)	$uckafr33	1	12 Jan 2007, 11:12
		If 5^21 X 4^11 = 2 X 10^n What is n? 1)11 2)21 3)23	tinman1412	4	06 Aug 2007, 18:03
		The state owned Agricultural Bank of China mopped up $22.1	daagh	2	04 Oct 2010, 00:16
		Sequence S is defined as follows: S1=2, S2=2^1, S3=2^2, SN=2	BN1989	1	21 Mar 2012, 05:18
	3	1+ 2.2^1 + 3.2^2 + 4.2^3 + ... + 100.2^99 = ?	mihir66	9	24 Feb 2013, 02:04

2^2-1) (2^2+1) (2^4+4) (2^8+1)= (a)2^16-1 (b)2^16+1

Main navigation

GMAT Resources

Partners

MBA Resources

GMAT ® is a registered trademark of the Graduate Management Admission Council ® (GMAC ®). GMAT Club's website has not been reviewed or endorsed by GMAC.

GMAT Courses

Admissions Consulting

2^2-1) (2^2+1) (2^4+4) (2^8+1)= (a)2^16-1 (b)2^16+1

2^2-1) (2^2+1) (2^4+4) (2^8+1)= (a)2^16-1 (b)2^16+1

Main navigation

GMAT Resources

Partners

MBA Resources