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# 2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!.

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2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!. [#permalink]  16 Jan 2004, 09:54
2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!. Find the product PQ.
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shubhangi

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working?
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shubhangi

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Kudos [?]: 10 [0], given: 0

2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!.

7!*8!/9!=

1*2*3*4*5*6*7/9

1*2*3*2*2*5*2*3*7/3*3

1*2*2*2*5*2*7/1

2^4, 3^0

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Agree with you Stoolfi. I also got p=4 q=0. Just a slight detail about the question asking for the product of PQ, not the sum. So answer should be 0?
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Paul

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I think you are right, Paul...
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