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2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!.

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2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!. [#permalink] New post 16 Jan 2004, 10:54
2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!. Find the product PQ.
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 [#permalink] New post 16 Jan 2004, 11:29
:( working?
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 [#permalink] New post 16 Jan 2004, 12:20
2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!.

7!*8!/9!=

1*2*3*4*5*6*7/9

1*2*3*2*2*5*2*3*7/3*3

1*2*2*2*5*2*7/1

2^4, 3^0

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 [#permalink] New post 16 Jan 2004, 12:28
Agree with you Stoolfi. I also got p=4 q=0. Just a slight detail about the question asking for the product of PQ, not the sum. So answer should be 0?
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 [#permalink] New post 16 Jan 2004, 12:33
I think you are right, Paul...
  [#permalink] 16 Jan 2004, 12:33
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2^P)*(3^Q) is the greatest positive divisor of 7!*8!/9!.

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