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2^p*4^2q=? 1. p-2q=0 2.p-q=0

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2^p*4^2q=? 1. p-2q=0 2.p-q=0 [#permalink] New post 05 Oct 2003, 23:42
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2^p*4^2q=?
1. p-2q=0
2.p-q=0
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 [#permalink] New post 06 Oct 2003, 00:01
...=2^(p+4q)

(1) p=2q not suff
(2) p=q not suff

combine: p=q=0, the initial stuff=1
C.
  [#permalink] 06 Oct 2003, 00:01
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2^p*4^2q=? 1. p-2q=0 2.p-q=0

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