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2 triangles

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Manager
Joined: 04 Dec 2008
Posts: 106
Followers: 1

Kudos [?]: 86 [0], given: 2

2 triangles [#permalink]  09 Jun 2009, 06:41
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Pls. explain. Thks!
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Gmat prep-2 triangles.doc [63.5 KiB]

Director
Joined: 03 Jun 2009
Posts: 803
Location: New Delhi
WE 1: 5.5 yrs in IT
Followers: 72

Kudos [?]: 488 [0], given: 56

Re: 2 triangles [#permalink]  09 Jun 2009, 07:23
Attachment:

solution.jpg [ 13.46 KiB | Viewed 599 times ]

These are similar triangles. Similar triangles have sides in the same ratio.
let height of triangles be h and H

Now, for smaller triangle, side s corresponds to height h
implies, side S corresponds to height H = h/s * S

Area of small triangle = 1/2*s*h
Area of larger triangle = 1/2*S*H = 1/2 *S* (h/s *S)

Given area of larger is twice area of smaller, hence
1/2 *S* (h/s *S) = 2 * (1/2 * s*h) --- solve this
or, S = s√2

_________________
Intern
Joined: 04 Mar 2008
Posts: 43
Followers: 0

Kudos [?]: 3 [0], given: 6

Re: 2 triangles [#permalink]  09 Jun 2009, 09:18
agree to the above explanation. The answer is C.
Manager
Joined: 28 Jan 2004
Posts: 203
Location: India
Followers: 2

Kudos [?]: 15 [0], given: 4

Re: 2 triangles [#permalink]  10 Jun 2009, 19:27
Since both triangles are similar , it does not matter what are the values of angles X,Y,Z.I assumed all to be 60 so it becomes an equilateral triangle.
Area of small triangle ,A1= (sqrt(3)s^2)/4
Area of Large triangle,A2 = (sqrt(3)S^2)/4
According to question,
A2 = 2A1
which easily gives S=sqrt(2)s

I followed this approach to avoiad calculating height (unnecessary calculation)
Re: 2 triangles   [#permalink] 10 Jun 2009, 19:27
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