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2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4.

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 [#permalink] New post 06 Jun 2003, 23:44
well, other option is to take 7^4 into account

7^4=2^11.229.....

therefore 2^x=2^39.229

therefore XYZ equals about 39.229*8*4
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 [#permalink] New post 06 Jun 2003, 23:49
Expert's post
skoper wrote:
well, other option is to take 7^4 into account

7^4=2^11.229.....

therefore 2^x=2^39.229

therefore XYZ equals about 39.229*8*4




I agree if X is not an integer.

A good point!


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 [#permalink] New post 08 Jun 2003, 01:06
comments Stolyar?
  [#permalink] 08 Jun 2003, 01:06
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2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4. yezz 7 12 Oct 2006, 15:49
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2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4.

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