2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4. : Quant Question Archive [LOCKED] - Page 2
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# 2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4.

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06 Jun 2003, 23:44
well, other option is to take 7^4 into account

7^4=2^11.229.....

therefore 2^x=2^39.229

therefore XYZ equals about 39.229*8*4
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06 Jun 2003, 23:49
skoper wrote:
well, other option is to take 7^4 into account

7^4=2^11.229.....

therefore 2^x=2^39.229

therefore XYZ equals about 39.229*8*4

I agree if X is not an integer.

A good point!

-=-
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08 Jun 2003, 01:06
08 Jun 2003, 01:06

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# 2^X)*(3^Y)*(5^Z) is the greatest positive divisor of (8!)^4.

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