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To tell the truth, it took me a minute to think about it. it seemed quite strange and unusual question - which makes it a good one. Of course, we might have approached it in a wrong way, but in any case, stolary is quite prolific.

This sort of problem is strange. Brstorewala knows about it. His approach is correct. BUT, it does not work when it comes to 10!*20!*30! When factorials are exceed 10, something strage happens... And I myself do not why.

stolyar,
i forgot to tell u about that 10!*20!*30! problem.....

try it out in the calculator of the computer (if u have patience) .........i think excel screws it up along the way........the answer with excel does not match with the answer from the calculator........

stolyar, i forgot to tell u about that 10!*20!*30! problem.....

try it out in the calculator of the computer (if u have patience) .........i think excel screws it up along the way........the answer with excel does not match with the answer from the calculator........

Yes, you are right. Excel may be overloaded with those factorials. Our approach should be OK.

You probably don't want to be sexist in your replies. It is he or she - you never know here I or Stolyar may be a lady.... actually I am pretty sure that Stolyar is a cute russian girl... she is just afraid to admit it cause all the guys will start annoying her.

So...

as to the solution,

Get the factors of 8!^4 = 8^4*7^4*6^4*5^4*4^4*3^4*2^4*1^4

Then compile out of 2, 3, adn 5 the largest possible divisors - you will take care of all of them except 7. So, you will need 2^12 to take care of 8^4, and so on at the end you will get 28 power for 2's, 8th power for 3's and 4th power for 5.

Is it clear now?

STOLYAR!

Last edited by bb on 07 Jun 2003, 00:13, edited 1 time in total.