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SVP
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Joined: 03 Feb 2003
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PS: EQUATION MOD [#permalink] New post 09 Jun 2003, 23:18
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Solve this one.

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Senior Manager
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Re: PS: EQUATION MOD [#permalink] New post 16 Apr 2006, 14:41
[quote="prashant"]Solutions are {-1/5, 3}[/quote]

How does one get this solution set?
please show your steps

Thank you,
Manager
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Re: PS: EQUATION MOD [#permalink] New post 17 Apr 2006, 22:44
trivikram wrote:
prashant wrote:
Solutions are {-1/5, 3}


Prof : Steps please....


Friends, this is a very old post. Guys with only 177 posts and that too someone who registered in 2003 would probably not be around.

You could solve it in the following manner:

The signs of the modulus would change in the following ranges:

z < -2, -2 <= z < 0, 0 <= z < 1, z >= 1

Solve for z in these ranges.
For z >= 1, you would get z = 3.
For 0 <= z < 1, you would get z = 3
For - 2 < z < 0, you would get z = - 1/5
For z < -2, you would get z - 1 (which is absurd if z < -2)

So the answer is z = - 1/5 and z = 3
_________________

Thanks,
Zooroopa

Re: PS: EQUATION MOD   [#permalink] 17 Apr 2006, 22:44
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