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2a+b)/(a+b)=? i) 3a/(a+b) =7 i) a+b =3

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Joined: 05 Apr 2005
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2a+b)/(a+b)=? i) 3a/(a+b) =7 i) a+b =3 [#permalink] New post 23 Sep 2005, 20:43
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(2a+b)/(a+b)=?

i) 3a/(a+b) =7
i) a+b =3
Senior Manager
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Joined: 30 Oct 2004
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 [#permalink] New post 23 Sep 2005, 20:55
(2a+b)/(a+b) can be simplified further to
(a/(a+b))+1

1) 3a/(a+b)=7 => a/(a+b) = 7/3, Plug in 7/3 above equation. Suff
2) a+b = 3 Insuff.

I think its (A).
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-Vikram

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Schools: Wharton'11 HBS'12
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 [#permalink] New post 24 Sep 2005, 07:41
I think 2a/(a+b) is simplified to

(b/(a+b))+1.....

vikramm wrote:
(2a+b)/(a+b) can be simplified further to
(a/(a+b))+1

1) 3a/(a+b)=7 => a/(a+b) = 7/3, Plug in 7/3 above equation. Suff
2) a+b = 3 Insuff.

I think its (A).
Senior Manager
Senior Manager
avatar
Joined: 30 Oct 2004
Posts: 289
Followers: 1

Kudos [?]: 8 [0], given: 0

 [#permalink] New post 24 Sep 2005, 07:50
(2a+b)/(a+b) = (a+a+b)/(a+b) = (a/(a+b)) + (a+b)/(a+b)
=(a/(a+b)) + 1
_________________

-Vikram

  [#permalink] 24 Sep 2005, 07:50
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2a+b)/(a+b)=? i) 3a/(a+b) =7 i) a+b =3

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