Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 27 Jun 2016, 02:28

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# 3 archers

Author Message
TAGS:

### Hide Tags

Director
Joined: 07 Jun 2004
Posts: 613
Location: PA
Followers: 3

Kudos [?]: 545 [0], given: 22

### Show Tags

08 Nov 2010, 03:51
00:00

Difficulty:

35% (medium)

Question Stats:

63% (01:41) correct 38% (01:15) wrong based on 16 sessions

### HideShow timer Statistics

Three archers each have an equal chance of hitting a target, and if only two of the three shoot the likelihood of the two hitting the target is 4/9 . What is the likelihood of all three men missing the target?

(A) 1/27
(B) 16/81
(C) 8/27
(D) 19/27
(E) 26/27
[Reveal] Spoiler: OA

_________________

If the Q jogged your mind do Kudos me : )

Math Expert
Joined: 02 Sep 2009
Posts: 33512
Followers: 5934

Kudos [?]: 73567 [1] , given: 9902

### Show Tags

08 Nov 2010, 04:14
1
KUDOS
Expert's post
rxs0005 wrote:
Three archers each have an equal chance of hitting a target, and if only two of the three shoot the likelihood of the two hitting the target is 4/9 . What is the likelihood of all three men missing the target?

(A) 1/27
(B) 16/81
(C) 8/27
(D) 19/27
(E) 26/27

Let the probability of an archer hitting a target be $$x$$. Then the probability of two hitting the target will be $$P=x*x=\frac{4}{9}$$ --> $$x=\frac{2}{3}$$, so the probability of an archer missing the target will be $$P=1-\frac{2}{3}=\frac{1}{3}$$.

The probability of all three men missing the target will be $$P=(\frac{1}{3})^3=\frac{1}{27}$$.

_________________
Re: 3 archers   [#permalink] 08 Nov 2010, 04:14
Similar topics Replies Last post
Similar
Topics:
1 3-3*6+2= 3 22 Jun 2016, 03:49
1 3 boys and 3 girls 9 19 Aug 2011, 23:59
26 3 + 3 + 3 + 2 × 3^2 + 2 × 3^3 + 2 × 3^4 + 2 × 3^5 + 2 × 3^6 11 03 Feb 2011, 16:16
3 3 + 3 + 3 + 2 × 3^2 + 2 × 3^3 + 2 × 3^4 + 2 × 3^5 + 2 × 3^6 4 22 Dec 2009, 08:17
9 3 + 3 + 3 + 2 × 3^2 + 2 × 3^3 + 2 × 3^4 + 2 × 3^5 + 2 × 3^6 6 28 Oct 2009, 08:22
Display posts from previous: Sort by