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3 identical machines can produce 2x in 4 days. How many such

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Senior Manager
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3 identical machines can produce 2x in 4 days. How many such [#permalink] New post 06 May 2006, 03:28
3 identical machines can produce 2x in 4 days. How many such machines can produce 4x in 3 days?
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 [#permalink] New post 06 May 2006, 03:36
2x produced in 4 days by 3 machines
4xproduced in 4 days by 6 machines
4xproduced in 1days by 6*4 machines
4xproduced in 3days by (6*4)/3 machines =8 machines


Ans 8 machines
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 [#permalink] New post 15 May 2006, 14:55
this one confuses me.
Red Wings - how did you come up with that formulation?
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 [#permalink] New post 15 May 2006, 15:02
3 machines can produce 2x in 4 days
In 1 day they produce x/2
Then 1 machine can produce x/6 in 1 day
in 3 days, production = x/2
to produce 4x, 8 machines are required.
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 [#permalink] New post 16 May 2006, 04:35
I Solve such questions using this technique: - (Initially I convert the questions for 1 machine or 1worker etc.)
If 1 machine works, It produces 2x in 4*3 = 12 days.

So for 2x it takes No. of days = 12
for 4x it takes No. of days = 24.

it finishes in 24 days, then machine required = 1
if it finishes in 3 days, then machine required = 24/3 = 8 machines.

Always works this way.
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 [#permalink] New post 19 May 2006, 03:28
(3*4)/2x = (y*3)/4x where y is the no. of machines

=> y=8(ANS)
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Re: Work done by identical machines [#permalink] New post 19 May 2006, 08:54
getzgetzu wrote:
3 identical machines can produce 2x in 4 days. How many such machines can produce 4x in 3 days?


= 3 (4x/2x) (4/3)
= 8 machines
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 [#permalink] New post 19 May 2006, 13:35
8 machines as well.

My way is to feel that there is proportionnal rule between the number of machines working together and the rate of production.

So,
3 machines <=> 2x / 4 days
m machines <=> 4x / 3 days

Thus, m = 3 * (4x/3) / (2x/4) = 8
  [#permalink] 19 May 2006, 13:35
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