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3 machines have a productivity ratio of 1 to 2 to 5. All 3 [#permalink]
 16 Feb 2011, 04:34
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3 machines have a productivity ratio of 1 to 2 to 5. All 3 machines are working on a job for 3 hours. At the beginning of the 4th hour, the slowest machine breaks. It is fixed at the beginning of hour seven, and begins working again. The job is done in nine hours. What was the ratio of the work performed by the fastest machine as compared to the slowest? Options are not provided OA is
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Re: Ratio & Proportion [#permalink]
16 Feb 2011, 07:50
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3 machines have a productivity ratio of 1:2:5. all 3 machines are working on a job for 3 hours. at the beginning of the 4th hour, the slowest machine breaks. it is fixed at the beginning at hour 7, and begins working again. the job is done in 9 hours. what was the ratio of the work performed by the fastest machine to the work performed by the slowest? "3 machines have a productivity ratio of 1:2:5" means that in a time interval (1 hour, 1 year, ...) the first machine can produce 1 part (so it's the slowest one), the second can produce 2 parts and the third and fastest one can produce 5 parts. Now, the fastest machine worked for whole 9 hours thus produced 9*5=45 parts but the slowest machine worked only for 6 hours thus produced 6*1=6 parts, so the ratio of the work performed by the fastest machine to the work performed by the slowest is 45/6=15/2.
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Re: Ratio & Proportion [#permalink]
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ruturaj wrote: please explain how slowest machine works for 6 hours slowest machine worked 1st hour 2nd hour 3rd hour Got broken got fixed and returned to work at the beginning of the 7th hour so: 7th hour 8th hour 9th hour Total of 6 hours. So the slowest machine made 6 pieces, while the fastest machine made 45
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Re: Ratio & Proportion [#permalink]
16 Feb 2011, 04:49
1:2:5 Let's consider 1 work is done by the slowest machine in 1 hour. in first 3 hours; Work performed by 3 machines 1*3:2*3:5*3 From beginning of 4th hour until start of 7th hour, 3 hours elapsed. Work performed by 3 machines 0:2*3:5*3. First one is 0 work as it is broken. Job is done in nine hours; from start of 7th hour until end of 9th hour, 3 hours elapsed. Work performed by 3 machines 1*3:2*3:5*3 Total work performed by slowest machine: 3+3=6 Total work performed by fastest machine: 15+15+15=45 Ratio = 45/6 = 15/2 Ans: 15/2
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Re: Ratio & Proportion [#permalink]
17 Feb 2011, 12:45
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Re: Ratio & Proportion [#permalink]
11 Aug 2011, 05:27
please explain how slowest machine works for 6 hours
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Re: Ratio & Proportion [#permalink]
11 Aug 2011, 08:02
ruturaj wrote: please explain how slowest machine works for 6 hours 3 machines have a productivity ratio of 1:2:5. all 3 machines are working on a job for 3 hours. at the beginning of the 4th hour, the slowest machine breaks. it is fixed at the beginning at hour 7, and begins working again. the job is done in 9 hours. what was the ratio of the work performed by the fastest machine to the work performed by the slowest? Productivity ratio of 1:2:5 means; In 1 hour: Slowest machine just finishes 1 workMedium fast machine finishes 2 workFastest machine finishes 5 work3 hours work: Slowest: 3*1=3 workMedium: 3*2=6 workFastest: 3*5=15 workTHEN SLOWEST BREAKS. It misses(3 hours): 4th hour 5th hour 6th hour During which: Medium fast completes: 3*2=6 workFastest completes: 3*5=15 workThen 7th, 8th, 9th hour(3 hours) Slowest: 3*1=3 workMedium: 3*2=6 workFastest: 3*5=15 workWork by fastest:Work by slowest 15+15+15: 3+345: 615: 2
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Re: Ratio & Proportion [#permalink]
12 Aug 2011, 00:22
0-1 fastest = 5 slowest = 1 1-2----5----------1 ---- 2-3 fastest = 5 ----1--- 6-7----5--------1-- 7-8----5---------1-- 8-9----5---------1-- hence total = 45 and 6 thus 15/2
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Re: Ratio & Proportion [#permalink]
12 Aug 2011, 02:03
+1 for explanation..
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Re: Ratio & Proportion [#permalink]
21 Aug 2011, 10:37
let's suppose that in 1 hour each machine produces 1+2+5 = 8 units in 3 hrs = 24 units next 3 hrs = 21 units (slowest isnt working) further 3 hrs = 24 untis fastest worked for 9 hours, while the slowest worked for 6 hrs. units produced by fastest / units produced by slowest = 9*5/6*1 = 15/2
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Re: Ratio & Proportion [#permalink]
21 Aug 2011, 14:29
Let M1 be the slowest and M3 be the fastest machine.
<---first 3 hours--><----3 hours----><---3 hours---->
M1 M1
M2 M2 M2
M3 M3 M3
productivity ratio = 1:2:5 (which is per hour)
x: 2x: 5x
work done by M3/ work done by M1 = (9*5x) / (6*x) = 45/6 = 15/2
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Re: Ratio & Proportion [#permalink]
02 Dec 2012, 22:49
The productivity ratio of the fastest machine to the slowest machine is 5:1.
The fastest machine worked for 9 straight hours. Thus, W = 5 x 9 = 45
The slowest machine brokedown in the 4th hour and was revived on the 7th hour. Thus, W = 1 x 6 = 6
The Output Ratio of fastest to slowest is 45 is to 6 ==> 15 : 2
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Re: Ratio & Proportion
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02 Dec 2012, 22:49
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