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# 3 people out of 5 women and 3 men are to be selected to sit

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Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

3 people out of 5 women and 3 men are to be selected to sit [#permalink]  20 Feb 2006, 16:11
3 people out of 5 women and 3 men are to be selected to sit on a comittee. How many combinations are there if there is to be at least 1 man???
Manager
Joined: 13 Dec 2005
Posts: 224
Location: Milwaukee,WI
Followers: 1

Kudos [?]: 7 [0], given: 0

If at least one M is to be selected .

then there are 3 scenarios

1M 2 W , 2M 1 W , 3M OW

so it will be (3c1 * 5c2 )+ (3c2 * 5c1 ) + (3c3 * 5c0)

= 30 + 15 + 1 =46 different ways
Manager
Joined: 20 Mar 2005
Posts: 201
Location: Colombia, South America
Followers: 1

Kudos [?]: 6 [0], given: 0

Re: Quick permutation question? [#permalink]  20 Feb 2006, 19:00
conocieur wrote:
3 people out of 5 women and 3 men are to be selected to sit on a comittee. How many combinations are there if there is to be at least 1 man???

3 * 7c2 = 63

Yes, 46 I got it wrong

is 8c3 - 5c3 or the way ipc did it too
Senior Manager
Joined: 11 Jan 2006
Posts: 270
Location: Chennai,India
Followers: 1

Kudos [?]: 3 [0], given: 0

5 w 3 m

mmm 3c3=1
+
mmw 3c2*5c1=3*5 =15
+
mww 3c1*5c2=3*10=30

thus 46
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