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# 3 tricky questions from GmatPrep!

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3 tricky questions from GmatPrep! [#permalink]

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28 Feb 2007, 04:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Could u help me out with these 3 questions?? The OA is the one circled in blue (while the other is the one i picked =( )

Please provide extensive explanation to the solution, cause i really don't know how to get it!!

Thanks

Riccardo
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28 Feb 2007, 08:17
1)

1) max dist: (6.4)(2) < 16
2) max dist: (1km/9min)*(60min/1hr)*(2hr) < 16

2)

if AC is diameter, ABC is a right angle.
A = (1/2)bh
Using the pythag. thrm,

A = (1/2)*(sqrt(2^2-1^2))*(1)
= sqrt(3)/2

3) couldnt think of a creative way to do this one..sorry
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28 Feb 2007, 08:49
3) not sure if the following is correct

h(n) = 2*(1*2*3*...n/2)
h(100) = 2*(1*2*3*...50)

since all prime numbers less than 50 are factors of h(100), they are not factors of h(100)+1
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28 Feb 2007, 12:27
The first question can be solved without any computations.

The question gives us conditions with regard to Time and Distance.

As one should already know, Rate x Time = Distance

Hence if any of the choices give an indication of the Rate we are sorted, since it will provide us with either a Yes or a No answer (which we don't need to work out in order to answer the question).

1) "less than 6.4 km/h" is an indication of Rate (which can of course be converted into mph)

2) "more than 9 minutes per km" is also an indication of Rate (which can be converted into km/h and than into mph)

For the third question, reason it this way:

h(100) = (2^50)*(1*2*3*...50)

h(100) is divisible by 2. So h(100)+1 is not divisible by 2, i.e. 2 is not a factor of h(100)+1.

h(100) is divisible by 3. So h(100)+1 is not divisible by 3, i.e. 3 is not a factor of h(100)+1.

.
.
.

h(100) is divisible by 50. So h(100)+1 is not divisible by 50, i.e. 50 is not a factor of h(100)+1.

Hence every prime number upto 50 is not a factor of h(100)+1.

So p > 50.

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28 Feb 2007, 13:18
kidstyx wrote:
The first question can be solved without any computations.

The question gives us conditions with regard to Time and Distance.

As one should already know, Rate x Time = Distance

Hence if any of the choices give an indication of the Rate we are sorted, since it will provide us with either a Yes or a No answer (which we don't need to work out in order to answer the question).

1) "less than 6.4 km/h" is an indication of Rate (which can of course be converted into mph)

2) "more than 9 minutes per km" is also an indication of Rate (which can be converted into km/h and than into mph)

For the third question, reason it this way:

h(100) = (2^50)*(1*2*3*...50)

h(100) is divisible by 2. So h(100)+1 is not divisible by 2, i.e. 2 is not a factor of h(100)+1.

h(100) is divisible by 3. So h(100)+1 is not divisible by 3, i.e. 3 is not a factor of h(100)+1.

.
.
.

h(100) is divisible by 50. So h(100)+1 is not divisible by 50, i.e. 50 is not a factor of h(100)+1.

Hence every prime number upto 50 is not a factor of h(100)+1.

So p > 50.

I disagree with you on number 1. We got the same answer but your logic is flawed IMO..
you say a calculation is not necessary.

We have an inequality not simply and equation with an "=" sign..

what if 1) said less than 9 km/hr?

the trip then could have taken less or more than 2 hours.

or what if from 1) and 2) we got some range of time?
1< time <3
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01 Mar 2007, 00:55
Yes, I'm wrong. Apologies.
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