30 people were invited to a dinner party. If 17 of the guest

Oldest

Best Reply

Author

Message

TAGS:

Director

Joined: 21 Dec 2009

Posts: 592

Concentration: Entrepreneurship, Finance

Followers: 13

Kudos [?]: 130 [0], given: 20

30 people were invited to a dinner party. If 17 of the guest [#permalink]

09 Dec 2012, 03:34

00:00

Question Stats:

0% (00:00) correct

0% (00:00) wrong

based on 0 sessions

Q1:
30 people were invited to a dinner party. If 17 of the guests fed on meal A, 15 on meal B, and 20 on meal C, what is the least number of people that could feed on all three meals?

A. 2
B. 3
C. 5
D. 6
E. 8

Q2 (related to Q1, with same options):
Supposing meal A=25, meal B=21, and meal C=20, but still with 30 total people. What is the minimum number of
people who eat all three meals?

A.2 B.3 C.5 D.6 E. 8

What are the specific clue to take rather than simply picking the smallest of the numbers in the option?
Kindly elaborate on ur strategy.
_________________

KUDOS me if you feel my contribution has helped you.

Last edited by Bunuel on 09 Dec 2012, 06:15, edited 2 times in total.

Renamed the topic and edited the question.

Manager

Joined: 31 May 2012

Posts: 126

Followers: 1

Kudos [?]: 23 [0], given: 49

Re: 30 people were invited to a dinner party [#permalink]

09 Dec 2012, 05:26

You can simplify the problem by considering below scenario.
"30 people, invited to a dinner party. Inviter has three different types of meal pases- A, B, C. He is going to distribute these in such that no one gets multiple passes of same type and least number of get all three passes."

In this question, answer is whatever number that is surplus of 60 i.e. (30 X 2).

Q 1) People=30
A= 17
B= 15
C= 20
Answer is 0. but to chose the least option in the given choices, I would choose 2 i.e. option A.

Q 2) People =30
A= 25
B=21
C=20
least number of people, who get 3 passes=
= (25+21+20)- 60
= 6
Answer is 6. Option D.

Below is one more similar analogy that will help to understand the problems.
There are 30 boxes placed in a row. You have three types of marbles- A, B & C. You are told place such that, no box hold 2 marbles of same type and least number of boxes should hold all types of marbles.

Consider below image of puts and marbles places inside.

Attachments

File comment: Analogy of marbles for the question.

answer.JPG [ 43.41 KiB | Viewed 570 times ]

SVP

Joined: 01 Sep 2010

Posts: 1749

Followers: 56

Kudos [?]: 582 [0], given: 467

Re: 30 people were invited to a dinner party [#permalink]

09 Dec 2012, 06:06

I do not understand completely the questions about these overlapping sets

if someoneclarify me please ??

I'm not sure , though, they are good question, do not seem gmat like. :?:

_________________

KUDOS is the good manner to help the entire community.

Manager

Joined: 04 Oct 2011

Posts: 228

Location: India

Concentration: Entrepreneurship, International Business

GMAT 1: 440 Q33 V13
GMAT 2: 0 Q0 V0

GPA: 3

Followers: 0

Kudos [?]: 17 [0], given: 44

Re: 30 people were invited to a dinner party [#permalink]

09 Dec 2012, 08:54

Hi umeshpatil

Q 2) People =30
A= 25
B=21
C=20
least number of people, who get 3 passes=
= (25+21+20)- 60
= 6
Answer is 6. Option D.

Can you explain this part ?
I didnt get this how u got 6?
_________________

GMAT - Practice, Patience, Persistence
Kudos if u like

Intern

Joined: 25 Jun 2012

Posts: 33

Followers: 0

Kudos [?]: 14 [0], given: 4

Re: 30 people were invited to a dinner party. If 17 of the guest [#permalink]

10 Dec 2012, 21:26

I disagree, I believe it is A, 2.

AnC- 15
BnC- 3
AnBnC- 2
B- 10

Intern

Joined: 24 Apr 2012

Posts: 44

Followers: 0

Kudos [?]: 7 [0], given: 1

Re: 30 people were invited to a dinner party. If 17 of the guest [#permalink]

11 Dec 2012, 05:39

[quote="gmatbull"]Q1:
30 people were invited to a dinner party. If 17 of the guests fed on meal A, 15 on meal B, and 20 on meal C, what is the least number of people that could feed on all three meals?

A. 2
B. 3
C. 5
D. 6
E. 8

Ans. We calculate people having only meal A , only meal B , only meal C and add them to 30. Then from the options the number giving us the least integer value is 2. Therefore the answer is (A).
_________________

www.mnemoniceducation.com

TURN ON YOUR MINDS!!!

Intern

Joined: 28 Aug 2012

Posts: 20

Concentration: Social Entrepreneurship

Followers: 0

Kudos [?]: 3 [0], given: 0

Re: 30 people were invited to a dinner party. If 17 of the guest [#permalink]

11 Dec 2012, 18:26

Hi,

How do you calculate the number of people who ate only meal A or meal B or meal C?

Thank you

Re: 30 people were invited to a dinner party. If 17 of the guest [#permalink] 11 Dec 2012, 18:26

		Similar topics	Author	Replies	Last post
Similar Topics:		Carla is having a dinner party and is inviting 5 guests, 3	acid_burn	12	19 Sep 2005, 14:51
		Of all the attendees at a dinner party, 40% were women. If	kidderek	3	14 Nov 2006, 14:03
		Of all the attendees at a dinner party, 40% were women. If	ggarr	1	17 Nov 2006, 15:35
		Of all the attendees at a dinner party, 40% were women. If	mm007	8	20 Dec 2006, 14:03
	2	Of all the attendees at a dinner party, 40% were women. If	enigma123	7	03 Nov 2011, 15:19

30 people were invited to a dinner party. If 17 of the guest

Main navigation

GMAT Resources

Partners

MBA Resources

GMAT ® is a registered trademark of the Graduate Management Admission Council ® (GMAC ®). GMAT Club's website has not been reviewed or endorsed by GMAC.

GMAT Courses

Admissions Consulting

30 people were invited to a dinner party. If 17 of the guest

30 people were invited to a dinner party. If 17 of the guest

Main navigation

GMAT Resources

Partners

MBA Resources