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35 - Probability

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Joined: 31 Dec 1969
Location: United States
Concentration: Marketing, Other
GMAT 1: 710 Q49 V38
GMAT 2: 660 Q V
GPA: 3.64
WE: Accounting (Accounting)
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Kudos [?]: 58 [0], given: 76079

35 - Probability [#permalink] New post 11 Nov 2004, 02:34
a question from the GMATCLUB forsaleqeustions:

what is the prob of bearing two boys from four born babies ?

a. 1/5
b. 1/8
c. 1/2
d. 3/8
e. 6/11
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 [#permalink] New post 11 Nov 2004, 02:59
Sweet and Simple Option c
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 [#permalink] New post 11 Nov 2004, 03:31
D) 3/8
Prob of getting boy: 1/2
Prob of getting girl: 1/2
Prob of getting exactly 2 boys and 2 girls: (1/2)^4
Pattern: BBGG --> 2 boys can take 4C2=6 different positions
Answer is 6/16 = 3/8
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 [#permalink] New post 11 Nov 2004, 11:58
yeah paul, u are correct

conceiving 2 boys from 4 babies can be possible in 4C2 = 6 ways
and probability to get boy baby / gal baby is (1/2)

So the probability to get exactly 2 boy babies - 6 * (1/2)^4 = 3/8
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 [#permalink] New post 17 Nov 2004, 06:02
total outcomes 1/2^4=16

possible combinations



B1 G G B2
B2 G G B1
B1 G B2 G
B2 G B1 G
G B1 B2 G
G B2 B1 G

so ...... 6/16=3/8
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Jim

Joined: 31 Dec 1969
Location: United States
Concentration: Marketing, Other
GMAT 1: 710 Q49 V38
GMAT 2: 660 Q V
GPA: 3.64
WE: Accounting (Accounting)
Followers: 0

Kudos [?]: 58 [0], given: 76079

 [#permalink] New post 17 Nov 2004, 09:04
using binominal formula will give a straightforward answer: ( 1/2+1/2)^4 gives all posible outcomes.
  [#permalink] 17 Nov 2004, 09:04
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