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# 35 - Probability

Author Message
TAGS:
Joined: 31 Dec 1969
Location: India
Concentration: General Management, Strategy
GMAT 1: 710 Q49 V0
GMAT 2: 740 Q40 V50
GMAT 3: 700 Q48 V38
GPA: 3.6
Followers: 0

Kudos [?]: 89 [0], given: 87105

35 - Probability [#permalink]  11 Nov 2004, 02:34
a question from the GMATCLUB forsaleqeustions:

what is the prob of bearing two boys from four born babies ?

a. 1/5
b. 1/8
c. 1/2
d. 3/8
e. 6/11
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Senior Manager
Joined: 16 Aug 2004
Posts: 327
Location: India
Followers: 1

Kudos [?]: 40 [0], given: 0

Sweet and Simple Option c
GMAT Club Legend
Joined: 15 Dec 2003
Posts: 4313
Followers: 27

Kudos [?]: 216 [0], given: 0

D) 3/8
Prob of getting boy: 1/2
Prob of getting girl: 1/2
Prob of getting exactly 2 boys and 2 girls: (1/2)^4
Pattern: BBGG --> 2 boys can take 4C2=6 different positions
_________________

Best Regards,

Paul

Senior Manager
Joined: 06 Dec 2003
Posts: 366
Location: India
Followers: 1

Kudos [?]: 4 [0], given: 0

yeah paul, u are correct

conceiving 2 boys from 4 babies can be possible in 4C2 = 6 ways
and probability to get boy baby / gal baby is (1/2)

So the probability to get exactly 2 boy babies - 6 * (1/2)^4 = 3/8
_________________

Perseverance, Hard Work and self confidence

Manager
Joined: 28 Jul 2004
Posts: 54
Followers: 1

Kudos [?]: 0 [0], given: 0

total outcomes 1/2^4=16

possible combinations

B1 G G B2
B2 G G B1
B1 G B2 G
B2 G B1 G
G B1 B2 G
G B2 B1 G

so ...... 6/16=3/8
_________________

Jim

Joined: 31 Dec 1969
Location: India
Concentration: General Management, Strategy
GMAT 1: 710 Q49 V0
GMAT 2: 740 Q40 V50
GMAT 3: 700 Q48 V38
GPA: 3.6
Followers: 0

Kudos [?]: 89 [0], given: 87105

using binominal formula will give a straightforward answer: ( 1/2+1/2)^4 gives all posible outcomes.
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