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3x^2 + 2x - 8 =

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3x^2 + 2x - 8 = [#permalink] New post 13 May 2012, 21:53
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

88% (01:46) correct 12% (00:30) wrong based on 41 sessions
3x^2 + 2x - 8 =

A. (3x-4)(x-2)
B. (3x-4)(x+2)
C. (3x-4)(x-2)
D. (3x-2)(x+4)
E. none of above
[Reveal] Spoiler: OA
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Re: 3x^2 + 2x - 8 = [#permalink] New post 13 May 2012, 22:15
3x^2 + 2x - 8
= 3x^2 + 6x - 4x - 8
= 3x (x + 2) - 4 (x+2)
= (3x-4) (x+2)

Option B
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Re: 3x^2 + 2x - 8 = [#permalink] New post 13 May 2012, 23:09
Expert's post
malkov wrote:
3x^2 + 2x - 8 =

A. (3x-4)(x-2)
B. (3x-4)(x+2)
C. (3x-4)(x-2)
D. (3x-2)(x+4)
E. none of above


Solving and Factoring Quadratics:
http://www.purplemath.com/modules/solvquad.htm
http://www.purplemath.com/modules/factquad.htm

Hope it helps.
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Re: 3x^2 + 2x - 8 = [#permalink] New post 14 May 2012, 00:05
3x^2 + 2x - 8

X1*X2=-8/3
X1+X2=-2/3

Only option B satisfies these parameters
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Re: 3x^2 + 2x - 8 =   [#permalink] 14 May 2012, 00:05
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