i'm getting 13/28 but that's not a choice...
I am also getting 13/28
can you explain how you got 6c2 and 8c2? combination is one of my weak areas...
Here total number of choice for TV set is 8 (2 b&w ; 6 color ) , by combination logic if we have to select two TV set out of 8 , it is
Now if we have to find the pobability that atleast 1 TV is B&W , easier method is to find the probability of no B&W TV chosen which means 2 TV sets are chosen from 6 color TV ; by the same logic explained above , number of way we can select 2 TV out of 6 will be 6c2. And so probability of chosing 2 TV set from 6 color TV set will be 6c2/8c2 .
To get aleast one B&W TV , we simply subtract 6c2/8c2 from 1 .