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4 A shipment of 8 television sets contains 2 black-and-white

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4 A shipment of 8 television sets contains 2 black-and-white [#permalink] New post 14 May 2008, 11:36
00:00
A
B
C
D
E

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(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
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4
A shipment of 8 television sets contains 2 black-and-white sets and 6color sets. If 2
television sets are to be chosen at random from this shipment, what is the probability
that at least 1 of the 2 sets chosen will be a black-and-white set?
A. 1/7 B. ¼ C. 5/14 D. 11/28 E. 13/26

Pls explain your answers.
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Re: PS-Tvs [#permalink] New post 14 May 2008, 11:49
i'm getting 13/28 but that's not a choice...
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Re: PS-Tvs [#permalink] New post 14 May 2008, 12:00
young_gun wrote:
i'm getting 13/28 but that's not a choice...



I am also getting 13/28

1-6c2/8c2
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Re: PS-Tvs [#permalink] New post 14 May 2008, 12:09
young_gun wrote:
i'm getting 13/28 but that's not a choice...


1 - (6/8)(5/7)

The answer choices are broken.
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Re: PS-Tvs [#permalink] New post 14 May 2008, 12:35
kidderek wrote:
young_gun wrote:
i'm getting 13/28 but that's not a choice...


1 - (6/8)(5/7)

The answer choices are broken.



Yep Iam getting 13/28 with the same approach. But the OA given for this problem is E.The problem is from Set 25
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Re: PS-Tvs [#permalink] New post 14 May 2008, 19:05
rpmodi wrote:
young_gun wrote:
i'm getting 13/28 but that's not a choice...



I am also getting 13/28

1-6c2/8c2


can you explain how you got 6c2 and 8c2? combination is one of my weak areas...
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Re: PS-Tvs [#permalink] New post 14 May 2008, 22:24
seongbae wrote:
rpmodi wrote:
young_gun wrote:
i'm getting 13/28 but that's not a choice...



I am also getting 13/28

1-6c2/8c2


can you explain how you got 6c2 and 8c2? combination is one of my weak areas...


seongbae ,

Here total number of choice for TV set is 8 (2 b&w ; 6 color ) , by combination logic if we have to select two TV set out of 8 , it is

8c2= 8!/(2!(8-2))!

Now if we have to find the pobability that atleast 1 TV is B&W , easier method is to find the probability of no B&W TV chosen which means 2 TV sets are chosen from 6 color TV ; by the same logic explained above , number of way we can select 2 TV out of 6 will be 6c2. And so probability of chosing 2 TV set from 6 color TV set will be 6c2/8c2 .

To get aleast one B&W TV , we simply subtract 6c2/8c2 from 1 .
Re: PS-Tvs   [#permalink] 14 May 2008, 22:24
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4 A shipment of 8 television sets contains 2 black-and-white

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