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4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5-2 (B) 52 [#permalink]
15 Mar 2011, 16:40
Question Stats:
50% (01:41) correct
50% (00:56) wrong based on 0 sessions
4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5^-2 (B) 5^2 (C) 5^3 (D) 5^8 (E) 5^11
Last edited by banksy on 16 Mar 2011, 09:00, edited 1 time in total.
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Re: 4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5-2 (B) 52 [#permalink]
15 Mar 2011, 18:37
rewrite as: 25*(5/x) = (1/25)*(1/125) (5^3)/x = (1/(5^2))*(1/(5^3)) 1/x = (1/(5^2))*(1/(5^3))*(1/(5^3)) 1/x = 1/(5^7) x = (5^7)
Where did you get that answer?
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Re: 4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5-2 (B) 52 [#permalink]
15 Mar 2011, 21:49
=> 125/x = 1/25 * 1/125 => x = 5^3 * 5^2 * 5^3 => x = 5^8 Perhaps the answer is D. I think the answer choices should read 5^-2, 5^2, 5^3, 5^8, 5^11. @banksy, could you please confirm the answer choices ?
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Re: 4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5-2 (B) 52 [#permalink]
16 Mar 2011, 05:11
Oops, I agree with the (5^8), bad adding skills.
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Re: 4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5-2 (B) 52 [#permalink]
16 Mar 2011, 05:21
Why isnt it
25/(x/5)=(1/25)/125 25*5/x=1/25*1/125 125/x=1/(125)(25) 1/x=1/25 x=25 x=5^2
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Re: 4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5-2 (B) 52 [#permalink]
16 Mar 2011, 05:36
scbguy wrote: Why isnt it
25/(x/5)=(1/25)/125 25*5/x=1/25*1/125 125/x=1/(125)(25) 1/x=1/25 x=25 x=5^2 \frac{125}{x} = \frac{1}{125*25}If we cross multiply; x = 125*125*25x = 5^3*5^3*5^2x = 5^{(3+3+2)} = 5^8
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Re: 4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5-2 (B) 52 [#permalink]
16 Mar 2011, 05:59
got it thanks  , i thought we could cancel out 125
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Re: 4. (GC) If 25/(x/5) = (1/25)/125 then x = ? (A) 5-2 (B) 52
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16 Mar 2011, 05:59
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