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4 men and 6 women finish a job in 8 days, while 3 men and 7

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Senior Manager
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Joined: 05 May 2003
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4 men and 6 women finish a job in 8 days, while 3 men and 7 [#permalink] New post 22 Jul 2004, 14:38
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

100% (01:01) correct 0% (00:00) wrong based on 1 sessions
4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. 10 women working together will finish it in :

A) 24 days
B) 32 days
C) 36 days
D) 40 days
E) 42 days
Director
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 [#permalink] New post 22 Jul 2004, 21:58
D.
Let m be a man's one day effort and w be a woman's one day effort.

4m+6y=1/8
3m+7y=1/10
10y=1/?? => ??=1/10y

12m+18y=3/8
12m+28y=4/10
=> 10y = 4/10-3/8 => 10y = 1/40

Hence ?? = 40 days.
Senior Manager
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 [#permalink] New post 23 Jul 2004, 00:18
Exactly..Got the same answer - 40days.
It has to be D.

hardworker_indian wrote:
D.
Let m be a man's one day effort and w be a woman's one day effort.

4m+6y=1/8
3m+7y=1/10
10y=1/?? => ??=1/10y

12m+18y=3/8
12m+28y=4/10
=> 10y = 4/10-3/8 => 10y = 1/40

Hence ?? = 40 days.

_________________

Awaiting response,

Thnx & Rgds,
Chandra

GMAT Club Legend
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 [#permalink] New post 24 Jul 2004, 05:30
4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. 10 women working together will finish it in

Hello everyone, why do we have to equate in term of efforts per day, instead of solving with simultaneous equation (which gives the wrong answer)

4m+6w = 8
3m+7w=10

So
12m+18w=24 (by multiplying 3 to 1st equation)
12m+28w=40 (by multiplying 4 to 2nd equation)

2nd equation minus 1st equation gives:

10w=16 day ???? WRONG !!
  [#permalink] 24 Jul 2004, 05:30
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4 men and 6 women finish a job in 8 days, while 3 men and 7

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