4 men and 6 women finish a job in 8 days, while 3 men and 7 : PS Archive
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# 4 men and 6 women finish a job in 8 days, while 3 men and 7

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Senior Manager
Joined: 05 May 2003
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4 men and 6 women finish a job in 8 days, while 3 men and 7 [#permalink]

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22 Jul 2004, 14:38
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4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. 10 women working together will finish it in :

A) 24 days
B) 32 days
C) 36 days
D) 40 days
E) 42 days
Director
Joined: 20 Jul 2004
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22 Jul 2004, 21:58
D.
Let m be a man's one day effort and w be a woman's one day effort.

4m+6y=1/8
3m+7y=1/10
10y=1/?? => ??=1/10y

12m+18y=3/8
12m+28y=4/10
=> 10y = 4/10-3/8 => 10y = 1/40

Hence ?? = 40 days.
Senior Manager
Joined: 22 Jun 2004
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23 Jul 2004, 00:18
Exactly..Got the same answer - 40days.
It has to be D.

hardworker_indian wrote:
D.
Let m be a man's one day effort and w be a woman's one day effort.

4m+6y=1/8
3m+7y=1/10
10y=1/?? => ??=1/10y

12m+18y=3/8
12m+28y=4/10
=> 10y = 4/10-3/8 => 10y = 1/40

Hence ?? = 40 days.

_________________

Awaiting response,

Thnx & Rgds,
Chandra

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Joined: 07 Jul 2004
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24 Jul 2004, 05:30
4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. 10 women working together will finish it in

Hello everyone, why do we have to equate in term of efforts per day, instead of solving with simultaneous equation (which gives the wrong answer)

4m+6w = 8
3m+7w=10

So
12m+18w=24 (by multiplying 3 to 1st equation)
12m+28w=40 (by multiplying 4 to 2nd equation)

2nd equation minus 1st equation gives:

10w=16 day ???? WRONG !!
24 Jul 2004, 05:30
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