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# 4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the

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Joined: 15 Aug 2003
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4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the [#permalink]  10 Oct 2003, 20:35
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4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the probability of

1. Picking one of each color

(4C1* 5C1*6C1 ) / (15C3) correct ?

2. Picking 3 of the same color.

( 4C3 + 5C3 + 6C3 ) / 15C3 correct ?

3. Picking 2 of the same color.

simpler way to do this??

thanks
praetorian
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Joined: 29 Aug 2003
Posts: 49
Location: Detroit, MI
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Kudos [?]: 2 [0], given: 0

Re: PS : Probability ... Colors [#permalink]  12 Oct 2003, 18:42
praetorian123 wrote:
4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the probability of

1. Picking one of each color

(4C1* 5C1*6C1 ) / (15C3) correct ?

2. Picking 3 of the same color.

( 4C3 + 5C3 + 6C3 ) / 15C3 correct ?

3. Picking 2 of the same color.

simpler way to do this??

thanks
praetorian

I would approach #3 like this.

(4C2*11C1 + 5C2*10C1 + 6C2*9C1)/15C3

Is this right?

Amar.
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Joined: 03 Feb 2003
Posts: 1607
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Re: PS : Probability ... Colors [#permalink]  13 Oct 2003, 00:10
praetorian123 wrote:
4 red , 5 blue, 6 yellow balls in a bag. Pick 3, whats the probability of

1. Picking one of each color

(4C1* 5C1*6C1 ) / (15C3) correct ?

2. Picking 3 of the same color.

( 4C3 + 5C3 + 6C3 ) / 15C3 correct ?

3. Picking 2 of the same color.

simpler way to do this??

thanks
praetorian

(1) agree
(2) agree
(3) if exactly two of the same color plus one of other color, then
(4C2*11 + 5C2*10 + 6C2*9) / 15C3

2 of red+1 of NOT red (11C1=11) and so on
Re: PS : Probability ... Colors   [#permalink] 13 Oct 2003, 00:10
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