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OK let me take a knock at this.....I am a bit rusty...

(48!+49!)/10^n

well lets first break 10^n into its prime factors 2^a * 5^b....well obviously the power of 5 will be the limiting case here, and so N cannot be greater than b.....

OK now lets re-write 48! +49! into something more easy...48!*50

oK so lets see how many 5s are there in 50,
50/5=10, 50/25=2, so there are 12 5s from 50...

now 48!, has a 5 from 5, 10, 15, 20, 30, 35, 40, 45 plus 2 5s from 25... so 48! gives 10 5s ....so in all as we can see....the power of N=12+10....22!

OK let me take a knock at this.....I am a bit rusty...

(48!+49!)/10^n

well lets first break 10^n into its prime factors 2^a * 5^b....well obviously the power of 5 will be the limiting case here, and so N cannot be greater than b.....

OK now lets re-write 48! +49! into something more easy...48!*50

oK so lets see how many 5s are there in 50, 50/5=10, 50/25=2, so there are 12 5s from 50...

now 48!, has a 5 from 5, 10, 15, 20, 30, 35, 40, 45 plus 2 5s from 25... so 48! gives 10 5s ....so in all as we can see....the power of N=12+10....22!

fresinha12, i guess you thought its 50! not 50.
50 has 2 5's
total: 10 + 2 = 12 _________________

Whether you think you can or think you can't. You're right! - Henry Ford (1863 - 1947)

OK let me take a knock at this.....I am a bit rusty...

(48!+49!)/10^n

well lets first break 10^n into its prime factors 2^a * 5^b....well obviously the power of 5 will be the limiting case here, and so N cannot be greater than b.....

OK now lets re-write 48! +49! into something more easy...48!*50

oK so lets see how many 5s are there in 50, 50/5=10, 50/25=2, so there are 12 5s from 50...

now 48!, has a 5 from 5, 10, 15, 20, 30, 35, 40, 45 plus 2 5s from 25... so 48! gives 10 5s ....so in all as we can see....the power of N=12+10....22!

fresinha12, i guess you thought its 50! not 50. 50 has 2 5's total: 10 + 2 = 12