5^21) * (4^11) = (2) * (10^n) n = : Quant Question Archive [LOCKED]
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# 5^21) * (4^11) = (2) * (10^n) n =

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5^21) * (4^11) = (2) * (10^n) n = [#permalink]

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15 Dec 2005, 14:38
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(5^21) * (4^11) = (2) * (10^n)

n = ?
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15 Dec 2005, 14:45
yb wrote:
(5^21) * (4^11) = (2) * (10^n)

n = ?

5^21 * 4^11 = (5^21) * (2^22) = (10^21) * 2

Therefore, n= 21.
Re: Exponents   [#permalink] 15 Dec 2005, 14:45
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# 5^21) * (4^11) = (2) * (10^n) n =

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