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5/9 part of the population in a Town are males

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5/9 part of the population in a Town are males [#permalink] New post 04 Feb 2013, 01:54
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A
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71% (01:53) correct 29% (01:26) wrong based on 7 sessions
5/9 part of the population in a Town are males. If 30% of the males are married, the percentage of unmarried females in the total population is:

a)20% b)27 7/9 % c)40% d)70 %
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Re: 5/9 part of the population in a Town are males [#permalink] New post 04 Feb 2013, 02:12
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guerrero25 wrote:
5/9 part of the population in a Town are males. If 30% of the males are married, the percentage of unmarried females in the total population is:

a)20% b)27 7/9 % c)40% d)70 %


Let the total population be 27 (9*3)

No. of males = 15
No. of married males = 5
So, No. of married females = 5. (Assuming none of the married men are polygamous or homosexual.. :P. I do not think the question can be solved without this assumption)

No. of unmarried females = 27 - 20 = 7

Percentage of unmarried females = 7/27 which is slightly higher than 25%.

So, answer should approximately B.

Not a very good question or answer choices..

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Re: 5/9 part of the population in a Town are males [#permalink] New post 04 Feb 2013, 02:18
guerrero25 wrote:
5/9 part of the population in a Town are males. If 30% of the males are married, the percentage of unmarried females in the total population is:

a)20% b)27 7/9 % c)40% d)70 %


Say the total population is 90 :
Number of males : 5/9 * 90 = 50
Number of females: 4/9 * 90 = 40

Males Females

Married 15 15
Unmarried 35 X

Total 50 40


Assuming that the number of males who is married is the same as the number of females who is too , this yield to 25/90 which is equal to 27 7/9 .

Answer : B

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Re: 5/9 part of the population in a Town are males   [#permalink] 04 Feb 2013, 02:18
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