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Hi everyone. Can anyone help me to solve these questions, please? Sorry, I don't know how to upload questions so everyone can see them. Thanks in advance!

Try uploading them as jpegs instead of docs.....that way members will be able to view the question in their explorer windows itself.... _________________

Hi everyone. Can anyone help me to solve these questions, please? Sorry, I don't know how to upload questions so everyone can see them. Thanks in advance!

Q 1 .See the attached figure.

Let the sides of the triangle be a, b and c Clearly using simple trigo calculations we can see that a=b= 5 and c= 5\sqrt{2} Now lets draw perpendicular on C with the height h. This perpendicular will bisect the side C, So let X= 1/2 x C = 1/2 x 5\sqrt{2}

Hi everyone. Can anyone help me to solve these questions, please? Sorry, I don't know how to upload questions so everyone can see them. Thanks in advance!

Q 2 See the attached figure.

Distance traveled = D = 2 pi R = 2pi = 2 x 3.14

where r = radius of the lake = 1 mile

Distance = speed x time Speed = 3 miles per hour time = Distance / speed =(2 x 3.14) / 3

Hi everyone. Can anyone help me to solve these questions, please? Sorry, I don't know how to upload questions so everyone can see them. Thanks in advance!

Method 1: There is a coordinate geometry formula that uses matrices to give you the area of a triangle whose coordinates are known. The final formula is: If the coordinates of a triangle are A(x1,y1), B(x2,y2) & C(x3,y3), then the area of the triangle is given by, 1/2* [(x1-x2)(y2-y3) - (y1-y2)(x2-x3)]

Applying we get, A(PQR) = 1/2* [(4-0)(3-4) - (0-3)(0-7)] = 1/2 [(-4) - (21)] = 1/2 [-25] .......... ignore the '-' sign = 12.5 ANS: A

Note: This method is also useful to decide whether the given 3 points form a triangle or they are collinear. If the area turns out to be zero, then the points are collinear.

Method 2: Drop perpendiculars from point R to the X and Y axes at points S(7,0) and T(0,4) respectively. Thus OSRT is a rectangle.

Now A(PQR) = A(OSRT) - A(OQP) - A(QRT) - A(PRS) where all the three triangles are right triangles. A(PQR) = 7*4 - (3*4/2) - (7*1/2) - (3*4/2) = 12.5 ANS: A

Method 3: Find out the lengths of the three sides using distance formula and then use the formula that calculates the area of a triangle from its sides. _________________

Hi everyone. Can anyone help me to solve these questions, please? Sorry, I don't know how to upload questions so everyone can see them. Thanks in advance!

The way u can represent the scores = 48, 48 , 70, 70, 70 , 80 , 80, 80, 80, 84 , 84 , 84, 84, 84, 84 , 84, 96, 96, 96,96

So clearly the Median = 84

See the figure for this question .

I don't know how to work on the 5th question may be some body can shed some light on this one.

Its given that the student worked for 20 days and earned: 48$ - on 2 days 70$ - on 3 days 80$ - on 4 days 84$ - on 7 days 96$ - on 4 days

For Median of even no of amounts, we need to arrange the amounts in ascending order and take the avg of the amounts placed in 10th and 11th positions => (84 + 84)/2 = 84

Method 1: There is a coordinate geometry formula that uses matrices to give you the area of a triangle whose coordinates are known. The final formula is: If the coordinates of a triangle are A(x1,y1), B(x2,y2) & C(x3,y3), then the area of the triangle is given by, 1/2* [(x1-x2)(y2-y3) - (y1-y2)(x2-x3)]

Applying we get, A(PQR) = 1/2* [(4-0)(3-4) - (0-3)(0-7)] = 1/2 [(-4) - (21)] = 1/2 [-25] .......... ignore the '-' sign = 12.5 ANS: A

Note: This method is also useful to decide whether the given 3 points form a triangle or they are collinear. If the area turns out to be zero, then the points are collinear.

Method 2: Drop perpendiculars from point R to the X and Y axes at points S(7,0) and T(0,4) respectively. Thus OSRT is a rectangle.

Now A(PQR) = A(OSRT) - A(OQP) - A(QRT) - A(PRS) where all the three triangles are right triangles. A(PQR) = 7*4 - (3*4/2) - (7*1/2) - (3*4/2) = 12.5 ANS: A

Method 3: Find out the lengths of the three sides using distance formula and then use the formula that calculates the area of a triangle from its sides.

Hey Sameer,

I was actually wondering if there is a faster way of solving this one and u just came up with that ..

Now we need to calculate the acceptable range for the observations measuring 1.5 SDs on either side of the mean => 8.1 + (0.3)*1.5 => 8.1 + 0.45 => 7.65 to 8.55

Except for 7.51 all the entries are within 1.5 SDs of the mean.

Hi everyone. Can anyone help me to solve these questions, please? Sorry, I don't know how to upload questions so everyone can see them. Thanks in advance!