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6 male and 8 female employees. A group has to be formed

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CEO
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Joined: 21 Jan 2007
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6 male and 8 female employees. A group has to be formed [#permalink] New post 22 Oct 2007, 07:16
00:00
A
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C
D
E

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6 male and 8 female employees. A group has to be formed including 2 men and 1 woman, How many possible variants?

60
80
120
150
180
Manager
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Joined: 18 Jun 2007
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Kudos [?]: 1 [0], given: 0

 [#permalink] New post 22 Oct 2007, 07:41
I'll give it a shot:
8 females, pick only 1. So i did: 8!/(1!7!) = 8
6 males, pick 2. 6!/(2!4!)= (6*5)/2 = 15

8*15 = 120
CEO
CEO
User avatar
Joined: 21 Jan 2007
Posts: 2770
Location: New York City
Followers: 6

Kudos [?]: 213 [0], given: 4

GMAT Tests User
 [#permalink] New post 22 Oct 2007, 08:38
ben928 wrote:
I'll give it a shot:
8 females, pick only 1. So i did: 8!/(1!7!) = 8
6 males, pick 2. 6!/(2!4!)= (6*5)/2 = 15

8*15 = 120


OA is C. 120


6c2 = 15
8c1= 8

15*8= 120
CEO
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Re: PS Easy Combo [#permalink] New post 22 Oct 2007, 21:13
bmwhype2 wrote:
6 male and 8 female employees. A group has to be formed including 2 men and 1 woman, How many possible variants?

60
80
120
150
180


6!/2!4! = number of possibilities for 2 men.

8!/7!1! = number of possibilities for 1 woman.

15*8=120.

C.
Re: PS Easy Combo   [#permalink] 22 Oct 2007, 21:13
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6 male and 8 female employees. A group has to be formed

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