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6 person sit around a table. In how many ways can they sit

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Director
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New post 26 May 2006, 04:50
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

6 person sit around a table. In how many ways can they sit so that no person has the same neighbors?
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New post 26 May 2006, 06:13
this one is a bit tricky... :)

Does the question asks for number of ways to sit so that no person has any two or one of the same neighbours?
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New post 31 May 2006, 02:27
Already discussed I guess:
Should be (n-1)!=5!
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New post 31 May 2006, 09:50
Can someone explain how you got to the answer? Or is this a straight formula you memorized?
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New post 31 May 2006, 10:36
tl372 wrote:
Can someone explain how you got to the answer? Or is this a straight formula you memorized?


This link can help you.

http://www.ilovemaths.com/3permcirc.htm
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New post 31 May 2006, 10:54
Great! Thanks M8.

I wonder how often people have seen circular permutations on the exam...
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New post 31 May 2006, 12:39
Its (n-1)!/2 i.e 60. But I calculated using another lengthy method.
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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6 person sit around a table. In how many ways can they sit

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