Answer: C

Explanation:

The number of digits (least) for \(10^n = (n+1)\) Where, \(n \geq 0\).

So, The number of digits (least) for \(10^{100}\) are \(100 + 1 = 101\)

Thus the answer is C.

Or, you can see that there are one hundred \(0's\) followed by \(1\) (to the right of \(1\)) and the least number of digits would be number of \(0's\) plus \(1\)

==> \(100+1=101\)

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