coolfish1103 wrote:

[(7^2)(2!)(4!)(6!)/9!]/14

= [7(2!)(4!)/(9)(8)]/14

= (4!)/(9)(8)

= 1/3

Quotient = 0

Remainder = 1

Is this right?

Quotient can be found out this way but not the remainder.

To find the remainder you can not cancel out the numbers.

Example

40/15: Quotient = 2 and remainder = 10

But if you consider 40/15 = 8/3 then Quotient is still 2 but remainder is 2 instead of 10.

For the main question if you want to find the remainder then do not can cancel out any number. This gonna take a long time and I hope this doesn't appear on real GMAT.

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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008