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# 7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent

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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent [#permalink]  09 Jun 2003, 23:54
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(7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent.
Manager
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skoper wrote:
i got 1/3

sorry, I guess that would make the quotient 0 then....with some remiander
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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent. [#permalink]  09 Jan 2006, 08:11
The quotient would be 4 with remainder 2

After solving I get 42/9 or 14/3.
Is this correct.
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Re: PS:QUOTINENT [#permalink]  09 Jan 2006, 11:51
[(7^2)(2!)(4!)(6!)/9!]/14

= [7(2!)(4!)/(9)(8)]/14

= (4!)/(9)(8)

= 1/3

Quotient = 0
Remainder = 1

Is this right?
CEO
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(7^2)*2!*4!*6!/9! =

= 7 * ((2 * 4) * 7 * 6!) * 3!/9!
= 7 * 3! * 8!/9!
= 42/9

Now dividing this by 14 yields 42/(9*14)

So Quotient = 0
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

CEO
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Re: PS:QUOTINENT [#permalink]  09 Jan 2006, 13:13
coolfish1103 wrote:
[(7^2)(2!)(4!)(6!)/9!]/14

= [7(2!)(4!)/(9)(8)]/14

= (4!)/(9)(8)

= 1/3

Quotient = 0
Remainder = 1

Is this right?

Quotient can be found out this way but not the remainder.

To find the remainder you can not cancel out the numbers.

Example
40/15: Quotient = 2 and remainder = 10

But if you consider 40/15 = 8/3 then Quotient is still 2 but remainder is 2 instead of 10.

For the main question if you want to find the remainder then do not can cancel out any number. This gonna take a long time and I hope this doesn't appear on real GMAT.
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Re: PS:QUOTINENT [#permalink]  09 Jan 2006, 13:37
ps_dahiya wrote:
Quotient can be found out this way but not the remainder.

To find the remainder you can not cancel out the numbers.

Example
40/15: Quotient = 2 and remainder = 10

But if you consider 40/15 = 8/3 then Quotient is still 2 but remainder is 2 instead of 10.

For the main question if you want to find the remainder then do not can cancel out any number. This gonna take a long time and I hope this doesn't appear on real GMAT.

so... for this particular problem do we have to multiply everything out or we can do the cancellations for everything except the 14 since we are suppose to divide by 14? (That might be easier?)
CEO
Joined: 20 Nov 2005
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Re: PS:QUOTINENT [#permalink]  09 Jan 2006, 14:07
coolfish1103 wrote:
ps_dahiya wrote:
Quotient can be found out this way but not the remainder.

To find the remainder you can not cancel out the numbers.

Example
40/15: Quotient = 2 and remainder = 10

But if you consider 40/15 = 8/3 then Quotient is still 2 but remainder is 2 instead of 10.

For the main question if you want to find the remainder then do not can cancel out any number. This gonna take a long time and I hope this doesn't appear on real GMAT.

so... for this particular problem do we have to multiply everything out or we can do the cancellations for everything except the 14 since we are suppose to divide by 14? (That might be easier?)

Calculate the terms on upper side and lower side sepertaly from the start and then find the remainder.
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Re: PS:QUOTINENT   [#permalink] 09 Jan 2006, 14:07
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