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7 people, A, B, C, D, E, F and H, go to a movie and sit next [#permalink]
28 Feb 2013, 11:50

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0% (00:00) correct
0% (00:00) wrong based on 1 sessions

7 people, A, B, C, D, E, F and H, go to a movie and sit next to each other in 8 adjacent seats in the front row of the theatre. In how many different arrangements will there be at least one person between A and F?

Re: 7 people, A, B, C, D, E, F and H, go to a movie and sit next [#permalink]
28 Feb 2013, 12:11

mun23 wrote:

7 people, A, B, C, D, E, F and H, go to a movie and sit next to each other in 8 adjacent seats in the front row of the theatre. In how many different arrangements will there be at least one person between A and F?

how this problem be solved?

We need to find at least one person between A and F which is equal to Total ways - No one between A and F Eight people can be arranged in 8! ways. No one between A and F is equal to 7!*2! (consider A and F as one. 7 people can be arranged in 7! and A and F in 2!)

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