punzoo wrote:

Hey Fellows,

Try this question.

Is a^2 + b^2 >= 130?

1. a/b = 3/11.

2. a < 3.

OA

.

I m confused between C n E. pls letme know where I m wrong.

clearly 2nd eq is not sufficient.

Take 1st eq... take a=3x and b =11x

put in the question.....we get \(9x^2 + 121x^2 >= 130\)

=> \(130x^2 >=130\)

\(x^2>=1\), thus we need to know whether this satisfy or not.

If we consider eq 2... a<3 that means x<1

Thus this should be C...but one case when x=1 we hav not consider this might take it to E.

Pls advice.

You did everything right, except the last step: \(x^2\geq{1}\) --> \(x\leq{-1}\) or \(x\geq{1}\) --> \(a\leq{-3}\) or \(a\geq{3}\). So still E.

You can use number plugging when considering statements together: For \(a=0.3\) and \(b=1.1\) answer is NO, but for \(a=-3\) and \(b=-11\) answer is YES.