Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 18 Jan 2017, 10:18

# STARTING SOON:

Open Admission Chat with MBA Experts of Personal MBA Coach - Join Chat Room to Participate.

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

Author Message
SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 245 [0], given: 0

### Show Tags

20 Jun 2003, 07:03
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

|Z|+|Z–1|=Z!
SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 245 [0], given: 0

### Show Tags

20 Jun 2003, 11:15
{0, 1} are OK now. Post your solution, not wild guessing.
SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 245 [0], given: 0

### Show Tags

12 Jun 2004, 00:15
A year is soon to pass by, but I see no solution here...
Manager
Joined: 07 May 2004
Posts: 183
Location: Ukraine, Russia(part-time)
Followers: 2

Kudos [?]: 15 [0], given: 0

### Show Tags

12 Jun 2004, 00:27
stolyar wrote:

|Z|+|Zâ€“1|=Z!

Z is natural number (or 0) => if Z >= 3 => Z! >= 6 and grows much faster than 2*Z - 1. => for Z >= 3, Z! > 2*Z - 1.

Z belongs to the set {0, 1, or 2}.

Z = 0: OK.

Z = 1: OK.

Z = 2: NO...

=> Z = {0, 1}.
SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 245 [0], given: 0

### Show Tags

13 Jun 2004, 12:34
yes, since Z is factorialized, it has to be a whole, nonnegative number. We can safely open |Z|.

Z+|Z-1|=Z!

Open the second modul.

1) if Z>1, then Z+Z-1=Z! or 2Z-1=Z!; no solution for whole Z>1
why? if Z>1, then the left part is always odd, while the right part is always even.

2) if 0<=Z<=1, then Z-Z+1=Z! or Z!=1; Z=[0 or 1]
Manager
Joined: 07 May 2004
Posts: 183
Location: Ukraine, Russia(part-time)
Followers: 2

Kudos [?]: 15 [0], given: 0

### Show Tags

17 Jun 2004, 08:55
lastochka wrote:
I don't see 1) or 2)
weird...

lastochka, stolyar merely stated that z-1 is greater than 0 or lower than 0.

The first case is equivalent to |z-1| = z - 1, the second one is equivalent to |z-1| = 1-z. Then he considers these 2 cases.
SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 245 [0], given: 0

### Show Tags

18 Jun 2004, 07:01
lastochka wrote:
I don't see 1) or 2)
weird...

Yes, many of my questions are weird and eerie. I like short but nonstandard problems. If you look back at the start of this forum, you will find tens of such questions.
18 Jun 2004, 07:01
Display posts from previous: Sort by