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Manager
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√ [#permalink] New post 08 Feb 2004, 07:45
260.

This is DS problem. Could anyone try it and show the workings?

---------
Is √(x тАУ 5)^2 = 5 тАУ x?

1. тАУx |x| > 0
2. 5 тАУ x > 0
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 [#permalink] New post 08 Feb 2004, 08:25
The problem is not clear
Can you please clarify whether

sqrt( sqr(x-5) ) = 5-x ?
or

sqr( sqrt(x-5) ) = 5-x ?
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 [#permalink] New post 08 Feb 2004, 08:30
You're right Anandk. To me, this question is just simplified to: X - 5 = 5 - X?
If so, then the only way this could be so is if X = 0
From 1) X < 0 so not sufficient
From 2) X < 5 so not sufficient
Both together are not sufficient so E is the answer
But I think this question is not well written...
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 [#permalink] New post 08 Feb 2004, 11:44
|x-5| = 5 -x

case 1: x>=5, x = 5
case 2: x<5, x E (-inf, 5)
Hence x E (-inf, 5]

(1) -x|x| < 0 => x E (-inf, 0)
(2) 5 -x > 0 => x E (-inf, 5)

Answer is D
  [#permalink] 08 Feb 2004, 11:44
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