Ok answer is 6C3 * 3C2
lets solve this question as
You have 6 positions and you need to place 3 people on that positions
How many ways you can do that
Similarly you have 3 positions and you want 2 people to take that position in how many ways they can do that
and they are mutually exclusive events i.e. there is no dependency of selection of guards on selection of forwards and vice versa
hence they should multiply
Therefore ,it is 6C3 * 3C2
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