Ok answer is 6C3 * 3C2

lets solve this question as

You have 6 positions and you need to place 3 people on that positions

How many ways you can do that

6C3 ways

Similarly you have 3 positions and you want 2 people to take that position in how many ways they can do that

3C2 ways

and they are mutually exclusive events i.e. there is no dependency of selection of guards on selection of forwards and vice versa

hence they should multiply

Therefore ,it is 6C3 * 3C2

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