Find all School-related info fast with the new School-Specific MBA Forum

It is currently 01 Aug 2015, 15:00
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

9 basketball players are trying out to be on a newly formed

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Manager
Manager
avatar
Affiliations: CFA Level 2 Candidate
Joined: 29 Jun 2009
Posts: 222
Schools: RD 2: Darden Class of 2012
Followers: 3

Kudos [?]: 95 [0], given: 2

9 basketball players are trying out to be on a newly formed [#permalink] New post 13 Oct 2009, 05:28
1
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

81% (02:03) correct 19% (01:09) wrong based on 127 sessions
9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?

A. 23
B. 30
C. 42
D. 60
E. 126
[Reveal] Spoiler: OA

Last edited by Bunuel on 27 Jul 2014, 23:11, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
Senior Manager
Senior Manager
User avatar
Affiliations: PMP
Joined: 13 Oct 2009
Posts: 312
Followers: 4

Kudos [?]: 117 [0], given: 37

Re: 9 basketball players are trying out to be on a newly formed [#permalink] New post 13 Oct 2009, 09:07
Agree on 60 , 6C3 * 3C2
_________________

Thanks, Sri
-------------------------------
keep uppp...ing the tempo...

Press +1 Kudos, if you think my post gave u a tiny tip

Manager
Manager
User avatar
Joined: 18 Jul 2009
Posts: 170
Location: India
Schools: South Asian B-schools
Followers: 2

Kudos [?]: 67 [0], given: 37

Re: 9 basketball players are trying out to be on a newly formed [#permalink] New post 13 Oct 2009, 09:15
6C3 x 3C2 :?
_________________

Bhushan S.
If you like my post....Consider it for Kudos :-D

Senior Manager
Senior Manager
User avatar
Joined: 18 Jun 2010
Posts: 302
Schools: Chicago Booth Class of 2013
Followers: 22

Kudos [?]: 156 [0], given: 194

Reviews Badge
Re: 9 basketball players are trying out to be on a newly formed [#permalink] New post 18 Aug 2010, 12:17
How do you get 6C3 * 3C2 ... ?
Manager
Manager
avatar
Status: Last few days....Have pressed the throttle
Joined: 20 Jun 2010
Posts: 71
WE 1: 6 years - Consulting
Followers: 3

Kudos [?]: 31 [0], given: 27

Re: 9 basketball players are trying out to be on a newly formed [#permalink] New post 19 Aug 2010, 01:59
Financier wrote:
How do you get 6C3 * 3C2 ... ?


Out of 6 gaurds we have to select 3 -> selection means we use C -> so 6C3

Out of 3 forwards we have to select 2 -> selection means we use C -> so 3C2

Total ways = 6C3 x 3C2 = 60

Hope this helps!
_________________

Consider giving Kudos if my post helps in some way

1 KUDOS received
Manager
Manager
avatar
Joined: 20 Apr 2010
Posts: 240
Location: Hyderabad
WE 1: 4.6 years Exp IT prof
Followers: 8

Kudos [?]: 30 [1] , given: 48

CAT Tests
Re: 9 basketball players are trying out to be on a newly formed [#permalink] New post 21 Aug 2010, 15:53
1
This post received
KUDOS
1
This post was
BOOKMARKED
Ok answer is 6C3 * 3C2

lets solve this question as
You have 6 positions and you need to place 3 people on that positions
How many ways you can do that
6C3 ways

Similarly you have 3 positions and you want 2 people to take that position in how many ways they can do that
3C2 ways

and they are mutually exclusive events i.e. there is no dependency of selection of guards on selection of forwards and vice versa
hence they should multiply

Therefore ,it is 6C3 * 3C2

I hope it helps let me know if it does if it does not you can always PM me.....!!!!
and don't forget to give a Kudos if you like the explanation....:-)
_________________

I will give a Fight till the End

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
- Bernard Edmonds

A person who is afraid of Failure can never succeed -- Amneet Padda

Don't Forget to give the KUDOS

1 KUDOS received
Math Forum Moderator
avatar
Joined: 20 Dec 2010
Posts: 2028
Followers: 140

Kudos [?]: 1181 [1] , given: 376

Re: Help! Comb [#permalink] New post 25 Feb 2011, 07:54
1
This post received
KUDOS
1
This post was
BOOKMARKED
9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?
a) 23
b) 30
c) 42
d) 60
e) 126

Sol:
3 guards of 6 guards AND 2 forwards of 3 forwards

\(C^6_3*C^3_2\)
\(\frac{6!}{3!3!}*\frac{3!}{2!1!}\)
\(\frac{6*5*4}{3*2}*\frac{3*2}{2}=60\)

Ans: "d"
_________________

~fluke

GMAT Club Premium Membership - big benefits and savings

1 KUDOS received
Manager
Manager
User avatar
Joined: 03 Sep 2010
Posts: 75
Location: Israel
GMAT 1: 660 Q47 V34
GMAT 2: 670 Q48 V34
GPA: 3.2
WE: Operations (Non-Profit and Government)
Followers: 3

Kudos [?]: 28 [1] , given: 2

Re: Help! Comb [#permalink] New post 25 Feb 2011, 08:04
1
This post received
KUDOS
D. 60.
Choose 3 guards out of 6 * choose 2 forwards out of 3.
(6!/(3!*3!)) * (3!/(2!*1!) = 20 *3 = 60.
1 KUDOS received
Manager
Manager
User avatar
Joined: 17 Feb 2011
Posts: 201
Concentration: Real Estate, Finance
Schools: MIT (Sloan) - Class of 2014
GMAT 1: 760 Q50 V44
Followers: 36

Kudos [?]: 569 [1] , given: 70

Re: Help! Comb [#permalink] New post 25 Feb 2011, 08:28
1
This post received
KUDOS
You have to proceed with 2 separate combinations:

6C3, which is the number of ways in which you can select 3 guards out of 6. This yields 20
3C2, which is the number of ways in which you can pick 2 forwards out of 3. This yields 3.

Multiply both and you get 60. Answer: D
GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 09 Sep 2013
Posts: 5708
Followers: 323

Kudos [?]: 63 [0], given: 0

Premium Member
Re: 9 basketball players are trying out to be on a newly formed [#permalink] New post 27 Jul 2014, 20:30
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

Intern
Intern
avatar
Joined: 23 Sep 2014
Posts: 15
Followers: 0

Kudos [?]: 0 [0], given: 6

Re: 9 basketball players are trying out to be on a newly formed [#permalink] New post 12 Dec 2014, 04:10
Hi guys,

just wondering if anyone could help me out with how to know whether the order matters. At first i thought it was just 6*5*4 times 3*2. I've been through a course and even with that i find it difficult to know when to apply combinations or permutations. Anyone have clear advice on this? Thanks in advance!
Re: 9 basketball players are trying out to be on a newly formed   [#permalink] 12 Dec 2014, 04:10
    Similar topics Author Replies Last post
Similar
Topics:
4 Experts publish their posts in the topic A basketball team composed of 12 players scored 100 points WarriorGmat 5 06 Jun 2013, 02:53
14 Experts publish their posts in the topic A basketball coach will select the members of a five-player Galiya 14 07 May 2012, 07:16
Experts publish their posts in the topic A basketball coach will select the members of a five-player Financier 5 17 Aug 2010, 10:27
29 Experts publish their posts in the topic John and Peter are among the nine players a basketball coach young_gun 31 31 Jul 2008, 15:56
7 Experts publish their posts in the topic John and Peter are among the nine players a basketball coach minhthel 7 17 Aug 2006, 19:41
Display posts from previous: Sort by

9 basketball players are trying out to be on a newly formed

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.