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# (999999)^2 - 1^2=

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Intern
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(999999)^2 - 1^2= [#permalink]  25 Aug 2003, 11:17
00:00

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(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
(999999)^2 - 1^2=
Intern
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Nope!!!

the answers choices were something like-

10^10-2

10^5(10^4-2)

10^5(10^5 )-2

I don't remember the answer choices correctly

I was getting 10^6-2(or something like this), which wasn't there
Manager
Joined: 14 Aug 2003
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(10^6-1)^2-1^2=10^12-2*10^6=10^6*(10^6-2)
Manager
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999999^2 - 1^2 = (999999 + 1)(999999 - 1 ) , right ??
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Brainless

Manager
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yes... in fact:
10^6*(10^6-2)=10^6*999,998=(999999 + 1)(999999 - 1 )
Manager
Joined: 10 Jun 2003
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VERY NICE!!!

Let's also remember that trick if it were to be 999999^2 -1.

Even if the question is not written as 1^2, we can re-write the question to nail this one!!!
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Sept 3rd

Manager
Joined: 28 Feb 2003
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(999999)^2 can be calculated easily by doing it in a straightforward way

9*9 = 81
99*99 = 9801
999*999 = 998001
hence
999999*999999 = 999998000001
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Too much is not enough...

Intern
Joined: 20 Aug 2003
Posts: 36
Location: USA
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bono wrote:
(999999)^2 can be calculated easily by doing it in a straightforward way

9*9 = 81
99*99 = 9801
999*999 = 998001
hence
999999*999999 = 999998000001

good.....but the answer choices do not require u to solve it this way.See my comments above.

The way javropu solved it is the right way.......
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