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a <-1 , is b between 0 and 1 1)-b<-a 2) -1<ab<0

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Senior Manager
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a <-1 , is b between 0 and 1 1)-b<-a 2) -1<ab<0 [#permalink] New post 06 Jun 2008, 04:26
a <-1 , is b between 0 and 1

1)-b<-a

2) -1<ab<0
Senior Manager
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Re: dont agree with the OA [#permalink] New post 06 Jun 2008, 04:33
Nihit wrote:
a <-1 , is b between 0 and 1

1)-b<-a

2) -1<ab<0


statement 1 can be converted to b<a.now a<=-1 so it can be -1 or less than -1 and b < a so b can be any number less than -1 . so there are multiple values possible given this statement
therefore insufficent

statement 2 says -1<ab<0 , given a<=-1 so b has to be between 0 and 1

therefore B is sufficent

IMO B

what is the OA for this one
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Senior Manager
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Re: dont agree with the OA [#permalink] New post 06 Jun 2008, 04:46
OA is B . I see my mistake now , thanks.
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Re: dont agree with the OA [#permalink] New post 06 Jun 2008, 05:15
Nihit wrote:
a <-1 , is b between 0 and 1

1)-b<-a

2) -1<ab<0


1: b>a, insuff.

2: b/c |A|>1, this means that B must be |B|<1 Thus B is less than 1 and B is greater than -1.

B is a fraction. Since ab is a negative number it must be positive and therefore lie btwn 0 & 1.
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Re: dont agree with the OA [#permalink] New post 06 Jun 2008, 11:02
B

Using stat 1, you know that b>a but b could be a negative fraction. insuff

Using stat 2, you know that b is negative because if it wasnt, then ab would be greater than 0
Re: dont agree with the OA   [#permalink] 06 Jun 2008, 11:02
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a <-1 , is b between 0 and 1 1)-b<-a 2) -1<ab<0

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