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A 48 gallon solution of salt and water is 10% salt. How many

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A 48 gallon solution of salt and water is 10% salt. How many [#permalink] New post 09 Sep 2004, 11:11
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15. A 48 gallon solution of salt and water is 10% salt. How many gallons of water must be added to the solution in order to decrease the salt to 8% of the volume?

(a) 8
(b) 12
(c) 13
(d) 14
(e) 16



. The “Racing magicâ€
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 [#permalink] New post 09 Sep 2004, 11:24
B & D respectively......!!

1. Salt remains same, hence 4.8 = 8/100 (48+x), where x is the gallons of water added. Solve for x!!

2. The First time they meet will be LCM of 120 and 90, which is 360 seconds or 6 minutes. The second time they will meet after another 6 minutes, hence they meet in 12 minutes. BTW, since CB makes 40 rounds in 1 hr, it takes 90 sec to make one round!!
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 [#permalink] New post 09 Sep 2004, 12:37
1. B.

4.8/(48+X) = 8/100
=> X= 12.


2. In circular races, A and B will meet at the starting point for the first time equal to the LCM of the time it takes A and B individually to complete one round along the circular track.

Racing magic takes 120 Sec's = 2min's.

Charging bull takes 60/40 = 3/2 = 1.5 mins.

LCM of 2 and 1.5 is 6. So, in 6 minutes they meet for the first time. They will meet at 12 mins the second time.
  [#permalink] 09 Sep 2004, 12:37
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A 48 gallon solution of salt and water is 10% salt. How many

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