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a and b are positive integers. What is the remainder of of

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a and b are positive integers. What is the remainder of of [#permalink] New post 25 Jun 2005, 19:53
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a and b are positive integers. What is the remainder of of (6*10^b + a - 1)/3 ?

S1) a = 2

S2) b = 5
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Re: DS: Remainder [#permalink] New post 25 Jun 2005, 20:14
AJB77 wrote:
a and b are positive integers. What is the remainder of of (6*10^b + a - 1)/3 ?

S1) a = 2

S2) b = 5


A would suffice. The remainder is 1.

B insufficient.

HMTG.
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 [#permalink] New post 25 Jun 2005, 20:15
It is A

(6*10^b + a - 1)/3 = 2*10^b + (a - 1)/3

So if we know a thats enough
  [#permalink] 25 Jun 2005, 20:15
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a and b are positive integers. What is the remainder of of

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