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# a and b are positive integers. What is the remainder of of

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Senior Manager
Joined: 30 May 2005
Posts: 374
Followers: 1

Kudos [?]: 7 [0], given: 0

a and b are positive integers. What is the remainder of of [#permalink]  25 Jun 2005, 18:53
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a and b are positive integers. What is the remainder of of (6*10^b + a - 1)/3 ?

S1) a = 2

S2) b = 5
Senior Manager
Joined: 17 Apr 2005
Posts: 375
Location: India
Followers: 1

Kudos [?]: 17 [0], given: 0

Re: DS: Remainder [#permalink]  25 Jun 2005, 19:14
AJB77 wrote:
a and b are positive integers. What is the remainder of of (6*10^b + a - 1)/3 ?

S1) a = 2

S2) b = 5

A would suffice. The remainder is 1.

B insufficient.

HMTG.
Director
Joined: 18 Feb 2005
Posts: 673
Followers: 1

Kudos [?]: 2 [0], given: 0

It is A

(6*10^b + a - 1)/3 = 2*10^b + (a - 1)/3

So if we know a thats enough
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